交换矩阵对角线的Python程序

给定一个 n*n 阶的方阵，你必须交换两条对角线的元素。
例子 ：

Input : matrix[][] = {1, 2, 3,
                      4, 5, 6,
                      7, 8, 9} 
Output : matrix[][] = {3, 2, 1,
                       4, 5, 6,
                       9, 8, 7} 

Input : matrix[][] = {4,  2,  3,  1,
                      5,  7,  6,  8,
                      9, 11, 10, 12,
                     16, 14, 15, 13} 
Output : matrix[][] = {1,  2,  3,  4,
                       5,  6,  7,  8,
                       9, 10, 11, 12,
                      11, 14, 15, 16}

解释：交换方阵的对角线背后的想法很简单。从 0 迭代到 n-1，每次迭代都必须交换 a[i][i] 和 a[i][ni-1]。

时间复杂度：O(n)

Python3

# Python program to interchange 
# the diagonals of matrix
N = 3;
  
# Function to interchange diagonals
def interchangeDiagonals(array):
  
    # swap elements of diagonal
    for i in range(N):
        if (i != N / 2):
            temp = array[i][i];
            array[i][i] = array[i][N - i - 1];
            array[i][N - i - 1] = temp;
          
    for i in range(N):
        for j in range(N):
            print(array[i][j], end = " ");
        print();
  
# Driver Code
if __name__ == '__main__':
    array = [ 4, 5, 6 ],[ 1, 2, 3 ],[ 7, 8, 9 ];
    interchangeDiagonals(array);
      
# This code is contributed by Rajput-Ji

输出：

6 5 4
 1 2 3
 9 8 7

请参阅完整的文章关于交换矩阵对角线的程序以获取更多详细信息！