📜  求系列 3, 7, 19, 55, 163, 的第 N 项。 . .

📅  最后修改于: 2022-05-13 01:56:10.345000             🧑  作者: Mango

求系列 3, 7, 19, 55, 163, 的第 N 项。 . .

给定一个正整数N 。任务是找到系列 3, 7, 19, 55, 163, ….. 的第 N

例子

方法:使用以下模式形成序列。对于任何值 N

插图:

下面是上述方法的实现:

C++
// C++ program to implement
// the above approach
#include 
using namespace std;
 
// Function to return Nth term
// of the series
int calcNum(int N)
{
    return 2 * pow(3, N - 1) + 1;
}
 
// Driver Code
int main()
{
    int N = 5;
    cout << calcNum(N);
    return 0;
}


Java
// Java code to implement the above approach
import java.lang.*;
public class gfg
{
     
    /* Function to return the Nth term of the series */
    static int calcNum(int N)
    {
        return (int)(2*(Math.pow(3,N-1))) + 1 ;
    }
 
    // Driver Code
    public static void main(String[] args)
    {
        int N = 5;
 
        System.out.println(calcNum(N));
    }
}
 
// This code is contributed by Abhishek Thakur


Python3
# Python3 program to implement
# the above approach
 
# Function to return Nth term
# of the series
def calcNum(N):
     
    return 2 * (3 ** (N - 1)) + 1
 
# Driver Code
N = 5
 
print(calcNum(N))
 
# This code is contributed by gfgking


C#
// C# code to implement the above approach
using System;
public class gfg
{
 
  /* Function to return the Nth term of the series */
  static int calcNum(int N)
  {
    return (int)(2 * (Math.Pow(3, N - 1))) + 1;
  }
 
  // Driver Code
  public static void Main(string[] args)
  {
    int N = 5;
 
    Console.WriteLine(calcNum(N));
  }
}
 
// This code is contributed by Abhishek Thakur


Javascript


输出
163

时间复杂度: O(1)

辅助空间: O(1)