用于在给定位置删除链表节点的 C++ 程序
给定一个单链表和一个位置,删除给定位置的链表节点。
例子:
Input: position = 1, Linked List = 8->2->3->1->7
Output: Linked List = 8->3->1->7
Input: position = 0, Linked List = 8->2->3->1->7
Output: Linked List = 2->3->1->7
如果要删除的节点是根节点,直接删除即可。要删除中间节点,我们必须有一个指向要删除的节点之前的节点的指针。因此,如果位置不为零,我们运行一个循环位置 1 次并获得指向前一个节点的指针。
下面是上述思想的实现。
C++
// A complete working C++ program to delete
// a node in a linked list at a given position
#include
using namespace std;
// A linked list node
class Node
{
public:
int data;
Node *next;
};
// Given a reference (pointer to pointer) to
// the head of a list and an int inserts a
// new node on the front of the list.
void push(Node** head_ref, int new_data)
{
Node* new_node = new Node();
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
// Given a reference (pointer to pointer) to
// the head of a list and a position, deletes
// the node at the given position
void deleteNode(Node **head_ref, int position)
{
// If linked list is empty
if (*head_ref == NULL)
return;
// Store head node
Node* temp = *head_ref;
// If head needs to be removed
if (position == 0)
{
// Change head
*head_ref = temp->next;
// Free old head
free(temp);
return;
}
// Find previous node of the node to be deleted
for(int i = 0; temp != NULL && i < position - 1; i++)
temp = temp->next;
// If position is more than number of nodes
if (temp == NULL || temp->next == NULL)
return;
// Node temp->next is the node to be deleted
// Store pointer to the next of node to be deleted
Node *next = temp->next->next;
// Unlink the node from linked list
free(temp->next); // Free memory
// Unlink the deleted node from list
temp->next = next;
}
// This function prints contents of linked
// list starting from the given node
void printList( Node *node)
{
while (node != NULL)
{
cout << node->data << " ";
node = node->next;
}
}
// Driver code
int main()
{
// Start with the empty list
Node* head = NULL;
push(&head, 7);
push(&head, 1);
push(&head, 3);
push(&head, 2);
push(&head, 8);
cout << "Created Linked List: ";
printList(head);
deleteNode(&head, 4);
cout << "
Linked List after Deletion at position 4: ";
printList(head);
return 0;
}
// This code is contributed by premsai2030
输出:
Created Linked List:
8 2 3 1 7
Linked List after Deletion at position 4:
8 2 3 1
有关详细信息,请参阅有关在给定位置删除链接列表节点的完整文章!