如果给定均值,则在数组中查找缺失的整数
给定一个大小为 N-1 的数组和 N 个元素的平均值(没有给出一个元素)。我们需要在数组中找到缺失值 X。
例子:
Input : a[] = {2, 4, 20}
Mean = 9
Output : Missing Element = 10
Explanation : Mean of (2, 4, 20, 10) is
(2 + 4 + 20 + 10)/4 = 9
令x为缺失元素
平均值 = (a 1 + a 2 + a 3 .. + X + ..a n )/N。
所以 (a 1 + a 2 + a 3 .. + X + ..a N ) = Mean*N 。
缺失元素 x = (Mean*N – (a 1 + a 2 + a 3 ....a N ))
C++
// C++ program to find missing element in a
// given array from mean.
#include
using namespace std;
// Size of a[] is N - 1 (one element missing)
int findMissing(int a[], int N, int mean)
{
// Find sum of array elements
int sum = 0;
for (int i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
int main() {
int a[] = {25, 65, 80};
int mean = 50;
int n = sizeof(a)/sizeof(a[0]);
cout << "The missing element : "
<< findMissing(a, n+1, mean) << endl;
return 0;
}
Java
// Java program to find missing element
// in a given array from mean.
import java.io.*;
class GFG
{
// Size of a[] is N - 1 (one element missing)
public static int findMissing(int a[], int N, int mean)
{
// Find sum of array elements
int sum = 0;
for (int i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
// Driver code
public static void main (String[] args)
{
int a[] = {25, 65, 80};
int mean = 50;
int n = a.length;
System.out.println("The missing element : "
+ findMissing(a, n + 1, mean));
}
}
// This code is contributed by upendra bartwal
Python3
# Python3 code to find missing element
# in a given array from mean.
# Size of a[] is N - 1
# (one element missing)
def findMissing( a , N , mean ):
# Find sum of array elements
sum = 0
for i in range(N - 1):
sum += a[i]
return (mean * N) - sum
# Driver Code
a = [25, 65, 80]
mean = 50
n = len(a)
print("The missing element : ", end = '')
print(findMissing(a, n+1, mean))
# This code is contributed by Sharad Bhardwaj.
C#
// C# program to find missing element
// in a given array from mean.
using System;
class GFG {
// Size of a[] is N - 1
// (one element missing)
public static int findMissing(int[] a, int N, int mean)
{
// Find sum of array elements
int sum = 0;
for (int i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
// Driver code
public static void Main()
{
int[] a = { 25, 65, 80 };
int mean = 50;
int n = a.Length;
Console.WriteLine("The missing element : "
+ findMissing(a, n + 1, mean));
}
}
// This code is contributed by vt_m.
PHP
Javascript
输出:
The missing element : 30