Python – 检查所有元组的元素差异是否小于 K

给定一个元组列表，检查每个元组的差值是否小于 K。

Input : test_list = [(3, 4), (1, 2), (7, 8), (9, 13)], K = 2
Output : False
Explanation : 13 – 9 = 4 > 2.

Input : test_list = [(3, 4), (1, 2), (7, 8)], K = 2
Output : True
Explanation : All have abs. diff 1 < 2.

方法#1：使用循环

在此，我们保留一个布尔变量并检查是否有任何元素大于或等于 K，然后将其标记为 False 并中断。

Python3

# Python3 code to demonstrate working of 
# Check if all tuples have element difference less than K
# Using loop
  
# initializing list
test_list = [(3, 4), (1, 2), (7, 8), (9, 8)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K 
K = 2
  
res = True 
for ele1, ele2 in test_list:
      
    # using abs() to compute absolute difference
    if abs(ele1 - ele2) >= K:
        res = False 
  
# printing result 
print("Are all elements difference less than K ? : " + str(res))

输出

The original list is : [(3, 4), (1, 2), (7, 8), (9, 8)]
Are all elements difference less than K ? : True

方法 #2：使用 all()

在这里，我们使用 all() 来检查所有元组是否在 K 中存在差异。

Python3

# Python3 code to demonstrate working of 
# Check if all tuples have element difference less than K
# Using all()
  
# initializing list
test_list = [(3, 4), (1, 2), (7, 8), (9, 8)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K 
K = 2
  
# shorthand to solve this problem
res = all(abs(sub1 - sub2) < K for sub1, sub2 in test_list)
  
# printing result 
print("Are all elements difference less than K ? : " + str(res))

输出

The original list is : [(3, 4), (1, 2), (7, 8), (9, 8)]
Are all elements difference less than K ? : True