Python|计算因子小于或等于给定 x 因子的数组元素

给定一个数组，任务是计算数组中因子小于给定数x的元素。

例子：

Input: arr = [2, 12, 4, 6], x = 6
Output: 2
factors of x = 6 is [1, 2, 3]
factors of arr[0] = 2 is [1]
factors of arr[1] = 12 is [1, 2, 3, 4]
factors of arr[2] = 4 is [1, 2]
factors of arr[3] = 6 is [1, 2, 3]

so only arr[0] and arr[2] are the answer.

方法：
找出所有元素的因数和给定x的因数，然后比较它们，如果元素的因数小于x的因数，则增加计数。

下面是上述问题的实现——

from math import ceil, sqrt
   
# function to count the factors of an array
def factorscount(x):
    count = 0
    for i in range(1,ceil(sqrt(x))):
        if x%i==i:
            count+=1
        else:
            count+=2
    return count
   
def Totalcount(arr, x):
      
    # count of factors of  given x
    count_fac = factorscount(x)
      
    # store the count of each factors
    arr_fac = [factorscount(i) for i in arr]
   
    ans = 0
   
    for i in arr_fac:
        # if factors count of element of array is
        #small than that of given number
        if i

输出：

2