查找三个元素中最小的元素的程序

给定三个数字。任务是在给定的三个数字中找到最小的数字。

例子：

Input: first = 15, second = 16, third = 10
Output: 10

Input: first = 5, second = 3, third = 6
Output: 3

方法：

1. 检查第一个元素是否小于第二个和第三个元素。如果是，则打印它。
2. 否则，检查第二个元素是否小于第一个和第三个元素。如果是，则打印它。
3. 其他三分之一是最小的元素并将其打印出来。

下面是上述方法的实现：

C++

// C++ implementation to find
// the smallest of three elements
#include 
using namespace std;
  
int main()
{
    int a = 5, b = 7, c = 10;
  
    if (a <= b && a <= c)
        cout << a << " is the smallest";
  
    else if (b <= a && b <= c)
        cout << b << " is the smallest";
  
    else
        cout << c << " is the smallest";
  
    return 0;
}

Java

// Java implementation to find
// the smallest of three elements
  
import java.io.*;
  
class GFG {
    
  
  
    public static void main (String[] args) {
            int a = 5, b = 7, c = 10;
  
    if (a <= b && a <= c)
        System.out.println( a + " is the smallest");
  
    else if (b <= a && b <= c)
        System.out.println( b + " is the smallest");
  
    else
        System.out.println( c + " is the smallest");
  
    }
}
// This code is contributed by shs..

Python3

# Python implementation to find
# the smallest of three elements
  
a, b, c = 5, 7, 10
  
if(a <= b and a <= c):
    print(a, "is the smallest")
  
elif(b <= a and b <= c):
    print(b, "is the smallest")
else:
    print(c, "is the smallest")
  
# This code is contributed 
# by 29AjayKumar

C#

// C# implementation to find 
// the smallest of three elements
using System;
  
class GFG
{
static public void Main ()
{
int a = 5, b = 7, c = 10; 
if (a <= b && a <= c) 
    Console.WriteLine( a + " is the smallest"); 
  
else if (b <= a && b <= c) 
    Console.WriteLine( b + " is the smallest"); 
  
else
    Console.WriteLine( c + " is the smallest"); 
}
}
  
// This code is contributed by jit_t

---

输出：

5 is the smallest

时间复杂度： O(1)