将八进制数转换为二进制数的程序

给定八进制数作为输入，任务是将该数字转换为二进制数。

例子：

Input : Octal = 345
Output : Binary = 011100101
Explanation : 
Equivalent binary value of 3: 011
Equivalent binary value of 4: 100
Equivalent binary value of 5: 101

Input : Octal = 120
Output : Binary = 001010000

八进制数：八进制数是一个位置数字系统，其基数或基数为8，并使用八个不同的符号。

二进制数：二进制数是以2为基的二进制数系统中表示的数字，它仅使用两个符号：0(零)和1(一)。

To convert an Octal number to Binary, the binary equivalent of each digit of the octal number is evaluated and combined at the end to get the equivalent binary number.

下面是上述方法的实现：

C++

// C++ program to convert
// Octal number to Binary
  
#include 
using namespace std;
  
// Function to convert an
// Octal to Binary Number
string OctToBin(string octnum)
{
    long int i = 0;
  
    string binary = "";
  
    while (octnum[i]) {
        switch (octnum[i]) {
        case '0':
            binary += "000";
            break;
        case '1':
            binary += "001";
            break;
        case '2':
            binary += "010";
            break;
        case '3':
            binary += "011";
            break;
        case '4':
            binary += "100";
            break;
        case '5':
            binary += "101";
            break;
        case '6':
            binary += "110";
            break;
        case '7':
            binary += "111";
            break;
        default:
            cout << "\nInvalid Octal Digit "
                 << octnum[i];
            break;
        }
        i++;
    }
  
    return binary;
}
  
// Driver code
int main()
{
    // Get the Hexadecimal number
    string octnum = "345";
  
    // Convert Ocatl to Binary
    cout << "Equivalent Binary Value = "
         << OctToBin(octnum);
  
    return 0;
}

Java

// Java program to convert
// Octal number to Binary
import java.util.*;
class Solution
{
   
// Function to convert an
// Octal to Binary Number
static String OctToBin(String octnum)
{
    long i = 0;
   
    String binary = "";
      
    while (iPython3

# Python3 program to convert
# Octal number to Binary
  
# defining a function that returns
# binary equivalent of the number
def OctToBin(octnum):
      
    binary = "" # initialising bin as String
      
    # While loop to extract each digit
    while octnum != 0:
          
        # extracting each digit
        d = int(octnum % 10)
        if d == 0:
              
            # concatination of string using join function
            binary = "".join(["000", binary])
        elif d == 1:
              
            # concatination of string using join function
            binary = "".join(["001", binary])
        elif d == 2:
              
            # concatination of string using join function
            binary = "".join(["010", binary])
        elif d == 3:
              
            # concatination of string using join function
            binary = "".join(["011", binary])
        elif d == 4:
              
            # concatination of string using join function
            binary = "".join(["100", binary])
        elif d == 5:
              
            # concatination of string using join function
            binary = "".join(["101", binary])
        elif d == 6:
              
            # concatination of string using join function
            binary = "".join(["110",binary])
        elif d == 7:
              
            # concatination of string using join function
            binary = "".join(["111", binary])
        else:
              
            # an option for invalid input
            binary = "Invalid Octal Digit"
            break
  
        # updating the oct for while loop
        octnum = int(octnum / 10)
          
    # returning the string binary that stores
    # binary equivalent of the number
    return binary
  
# Driver Code
octnum = 345
  
# value of function stored final_bin
final_bin = "" + OctToBin(octnum)
  
# result is printed
print("Equivalent Binary Value =", final_bin)
  
# This code is contributed by Animesh_Gupta



C#

// C# program to convert Octal number to Binary
  
class GFG
{
  
// Function to convert an
// Octal to Binary Number
static string OctToBin(string octnum)
{
    int i = 0;
  
    string binary = "";
      
    while (i < octnum.Length) 
    {
          
        char c = octnum[i];
        switch (c) 
        {
        case '0':
            binary += "000";
            break;
        case '1':
            binary += "001";
            break;
        case '2':
            binary += "010";
            break;
        case '3':
            binary += "011";
            break;
        case '4':
            binary += "100";
            break;
        case '5':
            binary += "101";
            break;
        case '6':
            binary += "110";
            break;
        case '7':
            binary += "111";
            break;
        default:
            System.Console.WriteLine( "\nInvalid Octal Digit "+ 
                                                    octnum[i]);
            break;
        }
        i++;
    }
  
    return binary;
}
  
// Driver code
static void Main()
{
    // Get the Hexadecimal number
    string octnum = "345";
  
    // Convert Ocatl to Binary
    System.Console.WriteLine("Equivalent Binary Value = " + 
                                         OctToBin(octnum));
}
}
  
// This code is contributed by mits

输出：

Equivalent Binary Value = 011100101