将二进制转换为八进制的程序
在此程序中,我们将首先将二进制数字转换为十进制。然后,十进制数字转换为八进制。
#include
#include
int convert(long long bin);
int main() {
long long bin;
printf("Enter a binary number: ");
scanf("%lld", &bin);
printf("%lld in binary = %d in octal", bin, convert(bin));
return 0;
}
int convert(long long bin) {
int oct = 0, dec = 0, i = 0;
// converting binary to decimal
while (bin != 0) {
dec += (bin % 10) * pow(2, i);
++i;
bin /= 10;
}
i = 1;
// converting to decimal to octal
while (dec != 0) {
oct += (dec % 8) * i;
dec /= 8;
i *= 10;
}
return oct;
}
输出
Enter a binary number: 101001
101001 in binary = 51 in octal
将八进制转换为二进制的程序
在此程序中,八进制数首先会转换为十进制。然后,将十进制数转换为二进制数。
#include
#include
long long convert(int oct);
int main() {
int oct;
printf("Enter an octal number: ");
scanf("%d", &oct);
printf("%d in octal = %lld in binary", oct, convert(oct));
return 0;
}
long long convert(int oct) {
int dec = 0, i = 0;
long long bin = 0;
// converting octal to decimal
while (oct != 0) {
dec += (oct % 10) * pow(8, i);
++i;
oct /= 10;
}
i = 1;
// converting decimal to binary
while (dec != 0) {
bin += (dec % 2) * i;
dec /= 2;
i *= 10;
}
return bin;
}
输出
Enter an octal number: 67
67 in octal = 110111 in binary