示例1:将二进制转换为八进制的程序
在此程序中,我们将首先将二进制数转换为十进制。然后,十进制数字转换为八进制。
public class BinaryOctal {
public static void main(String[] args) {
long binary = 101001;
int octal = convertBinarytoOctal(binary);
System.out.printf("%d in binary = %d in octal", binary, octal);
}
public static int convertBinarytoOctal(long binaryNumber)
{
int octalNumber = 0, decimalNumber = 0, i = 0;
while(binaryNumber != 0)
{
decimalNumber += (binaryNumber % 10) * Math.pow(2, i);
++i;
binaryNumber /= 10;
}
i = 1;
while (decimalNumber != 0)
{
octalNumber += (decimalNumber % 8) * i;
decimalNumber /= 8;
i *= 10;
}
return octalNumber;
}
}
输出
101001 in binary = 51 in octal
此转换发生为:
Binary To Decimal
1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 0 * 21 + 1 * 20 = 41
Decimal to Octal
8 | 41
8 | 5 -- 1
8 | 0 -- 5
(51)
示例2:将八进制转换为二进制的程序
在此程序中,八进制数首先从十进制转换为十进制。然后,将十进制数转换为二进制数。
public class OctalBinary {
public static void main(String[] args) {
int octal = 67;
long binary = convertOctalToBinary(octal);
System.out.printf("%d in octal = %d in binary", octal, binary);
}
public static long convertOctalToBinary(int octalNumber)
{
int decimalNumber = 0, i = 0;
long binaryNumber = 0;
while(octalNumber != 0)
{
decimalNumber += (octalNumber % 10) * Math.pow(8, i);
++i;
octalNumber/=10;
}
i = 1;
while (decimalNumber != 0)
{
binaryNumber += (decimalNumber % 2) * i;
decimalNumber /= 2;
i *= 10;
}
return binaryNumber;
}
}
输出
67 in octal = 110111 in binary
此转换发生为:
Octal To Decimal
6 * 81 + 7 * 80 = 55
Decimal to Binary
2 | 55
2 | 27 -- 1
2 | 13 -- 1
2 | 6 -- 1
2 | 3 -- 0
2 | 1 -- 1
2 | 0 -- 1
(110111)