给定数字n,任务是编写一个程序以找到第N个五倍体编号。五足动物数字是图形数字的类别,可以表示为规则和离散的几何图案。在帕斯卡三角形中,从第5个条件行1 4 6 4 1从右到左或从左到右开始的任何行的第五个单元格中的数字是五角形数。
例子 :
Input : 5
Output :70
Input :8
Output :1001
前五位数字是:
1,5,15,35,70,126,210,330,495,715,1001………
第N个五角位数的公式:
C++
// C++ Program to find the
// nth Pentatope Number
#include
using namespace std;
// Function that returns nth
// pentatope number
int pentatopeNum(int n)
{
return (n * (n + 1) * (n + 2) * (n + 3)) / 24;
}
// Drivers Code
int main()
{
// For 5th PentaTope Number
int n = 5;
cout << pentatopeNum(n) << endl;
// For 11th PentaTope Number
n = 11;
cout << pentatopeNum(n) << endl;
return 0;
}
Java
// Java Program to find the
// nth Pentatope Number
import java.io.*;
class GFG
{
// Function that returns nth
// pentatope number
static int pentatopeNum(int n)
{
return (n * (n + 1) *
(n + 2) * (n + 3)) / 24;
}
// Driver Code
public static void main (String[] args)
{
// For 5th PentaTope Number
int n = 5;
System.out.println(pentatopeNum(n));
// For 11th PentaTope Number
n = 11;
System.out.println(pentatopeNum(n));
}
}
// This code is contributed by m_kit
Python3
# Python3 program to find
# nth Pentatope number
# Function to calculate
# Pentatope number
def pentatopeNum(n):
# Formula to calculate nth
# Pentatope number
return (n * (n + 1) *
(n + 2) *
(n + 3) // 24)
# Driver Code
n = 5
print(pentatopeNum(n))
n = 11
print(pentatopeNum(n))
# This code is contributed
# by ajit.
C#
// C# Program to find the
// nth Pentatope Number
using System;
class GFG
{
// Function that returns
// nth pentatope number
static int pentatopeNum(int n)
{
return (n * (n + 1) *
(n + 2) * (n + 3)) / 24;
}
// Driver Code
static public void Main(String []args)
{
// For 5th PentaTope Number
int n = 5;
Console.WriteLine(pentatopeNum(n));
// For 11th PentaTope Number
n = 11;
Console.WriteLine(pentatopeNum(n));
}
}
// This code is contributed by Arnab Kundu
PHP
Javascript
输出 :
70
1001
参考: https : //en.wikipedia.org/wiki/Pentatope_number