Python中的 numpy.count()

numpy.core.defchararray.count(arr, substring, start=0, end=None) ：计算指定范围内子字符串的非重叠出现次数。

Parameters:
arr : array-like or string to be searched.
substring : substring to search for.
start, end : [int, optional] Range to search in.

Returns : An integer array with the number of non-overlapping occurrences of sub-string.

代码#1：

# Python Program illustrating 
# numpy.char.count() method 
  
import numpy as np 
  
# 2D array 
arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
  
print ("arr : ", arr)
  
print ("Count of 'tt'", np.char.count(arr, 'tt'))
print ("Count of 'tt'", np.char.count(arr, 'tt', start = 0))
print ("Count of 'tt'", np.char.count(arr, 'tt', start = 8))

输出：

arr :  ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
Count of 'tt' [2 2 1 0]
Count of 'tt' [2 2 1 0]
Count of 'tt' [1 2 1 0]

代码#2：

# Python Program illustrating 
# numpy.char.count() method 
import numpy as np 
  
# 2D array 
arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
  
print ("arr : ", arr)
  
print ("Count of 'Aa'", np.char.count(arr, 'Aa'))
print ("Count of 'Aa'", np.char.count(arr, 'Aa', start = 8))

输出：

arr :  ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']

Count of 'Aa' [1 1 1 1]
Count of 'Aa' [1 0 0 0]