MySQL 中的 BIT_OR()函数

MySQL 中的BIT_OR()函数用于返回给定表达式中所有位的按位或。它首先将所有十进制值转换为二进制值，然后对这些二进制值进行按位或运算。

句法：

BIT_OR(expr)

参数：此方法只接受一个参数。

表达式 –
我们要应用 BIT_OR函数的输入表达式。

返回：它返回给定表达式中所有位的按位或。

示例-1：
为了演示 BIT_OR函数的工作，我们必须首先创建一个名为 EmployeeDetails 的表。

CREATE TABLE EmployeeDetails(
Employee_Id INT AUTO_INCREMENT,  
Employee_Name VARCHAR(100) NOT NULL,
Working_At VARCHAR(20) NOT NULL,
Work_Location  VARCHAR(20) NOT NULL,
Joining_Date DATE NOT NULL,
Annual_Income INT  NOT NULL,
PRIMARY KEY(Employee_Id )
);

现在，将值插入表中 -

INSERT INTO EmployeeDetails (Employee_Name, Working_At, 
Work_Location, Joining_Date, Annual_Income)
VALUES
('Amit Khan', 'XYZ Digital', 'Kolkata', '2019-10-06', 350000),
('Shreetama Pal', 'ABC Corp.', 'Kolkata', '2018-12-16', 500000),
('Aniket Sharma', 'PQR Soln.', 'Delhi', '2020-01-11', 300000),
('Maitree Jana', 'XYZ Digital', 'Kolkata', '2019-05-01', 400000),
('Priyanka Ojha', 'ABC Corp.', 'Delhi', '2019-02-13', 350000),
('Sayani Mitra', 'XYZ Digital', 'Kolkata', '2019-09-15', 320000),
('Nitin Dey', 'PQR Soln.', 'Delhi', '2019-10-06', 250000),
('Sujata Samanta', 'PQR Soln.', 'Kolkata', '2020-10-06', 350000),
('Sudip Majhi', 'ABC Corp.', 'Delhi', '2018-10-30', 600000),
('Sanjoy Kohli', 'XYZ Digital', 'Delhi', '2019-04-18', 450000);

要验证使用以下命令如下 -

Select * FROM EmployeeDetails;

输出：

EMPLOYEE_ID	EMPLOYEE_NAME	WORKING_AT	WORK_LOCATION	JOINING_DATE	ANNUAL_INCOME
1	Amit Khan	XYZ Digital	Kolkata	2019-10-06	350000
2	Shreetama Pal	ABC Corp.	Kolkata	2018-12-16	500000
3	Aniket Sharma	PQR Soln.	Delhi	2020-01-11	300000
4	Maitree Jana	XYZ Digital	Kolkata	2019-05-01	400000
5	Priyanka Ojha	ABC Corp.	Delhi	2019-02-13	350000
6	Sayani Mitra	XYZ Digital	Kolkata	2019-09-15	320000
7	Nitin Dey	PQR Soln.	Delhi	2019-10-06	250000
8	Sujata Samanta	PQR Soln.	Kolkata	2020-10-06	350000
9	Sudip Majhi	ABC Corp.	Delhi	2018-10-30	600000
10	Sanjoy Kohli	XYZ Digital	Delhi	2019-04-18	450000

现在我们将从 EmployeeDetails 表中找到公司所有员工年收入的 BIT_OR。

SELECT Working_At, BIT_OR(Annual_Income) AS BITORINCOME 
FROM EmployeeDetails group by Working_At;

输出：

WORKING_AT	BITORINCOME
XYZ Digital	524272
ABC Corp.	1046512
PQR Soln.	514032

示例 2 ：
现在我们将从 EmployeeDetails 表中找到所有员工地点的年收入的 BIT_OR。

SELECT Work_Location, BIT_OR(Annual_Income) AS BITORINCOME 
FROM EmployeeDetails 
Group By Work_Location;

输出：

WORK_LOCATION	BITORINCOME
Kolkata	524208
Delhi	1048560

示例 3 ：
首先创建一个 StudentMarks 表 -

CREATE TABLE StudentMarks(
StudentId INT AUTO_INCREMENT,  
StudentName VARCHAR(100) NOT NULL,
Class VARCHAR(20) NOT NULL,
Roll INT NOT NULL,
Sub1Mark INT NOT NULL,
Sub2Mark INT NOT NULL,
Sub3Mark INT NOT NULL,
TotalMarks INT NOT NULL,
PRIMARY KEY(StudentId)
);

向表中插入数据——

INSERT INTO StudentMarks
(StudentName, Class, Roll, Sub1Mark, 
Sub2Mark, Sub3Mark, TotalMarks)
VALUES
('Amit Jana', 'V', 10100, 85, 80, 95, 260),
('Labanya Mallick', 'VI', 11000, 81, 89, 95, 265),
('Virat Sharma', 'VI', 12000, 75, 83, 90, 248),
('Sayani Samanta', 'V', 13000, 95, 90, 99, 284),
('Riyanka Panda', 'V', 14000, 70, 87, 88, 245),  
('Ritika Shah', 'VI', 15000, 78, 89, 90, 257);

要验证使用以下命令如下 -

SELECT  * From StudentMarks;

输出：

STUDENTID	STUDENTNAME	CLASS	ROLL	SUB1MARK	SUB2MARK	SUB3MARK	TOTALMARKS
1	Amit Jana	V	10100	85	80	95	260
2	Labanya Mallick	VI	11000	81	89	95	265
3	Virat Sharma	VI	12000	75	83	90	248
4	Sayani Samanta	V	13000	95	90	99	284
5	Riyanka Panda	V	14000	70	87	88	245
6	Ritika Shah	VI	15000	78	89	90	257

现在我们将从 StudentMarks 表中找到所有学生班级的总分的 BIT_OR。

SELECT Class, BIT_OR(TotalMarks) AS BITORMARKS 
FROM StudentMarks 
Group By Class;

输出：

CLASS	BITORMARKS
V	509
VI	505