MySQL 中的 BIT_XOR()函数
MySQL 中的BIT_XOR()函数用于返回给定表达式中所有位的按位异或。它首先将所有十进制值转换为二进制值,然后对这些二进制值执行按位异或运算。
句法 :
BIT_XOR(expr)
参数:此方法只接受一个参数。
- expr –我们要应用 BIT_XOR函数的输入表达式。
返回:它返回给定表达式中所有位的按位异或。
示例-1:
为了演示 BIT_XOR函数的工作,我们必须首先创建一个名为 EmployeeDetails 的表。
CREATE TABLE EmployeeDetails(
Employee_Id INT AUTO_INCREMENT,
Employee_Name VARCHAR(100) NOT NULL,
Working_At VARCHAR(20) NOT NULL,
Work_Location VARCHAR(20) NOT NULL,
Joining_Date DATE NOT NULL,
Annual_Income INT NOT NULL,
PRIMARY KEY(Employee_Id)
);
现在,将值插入表中 -
INSERT INTO EmployeeDetails (Employee_Name,
Working_At, Work_Location, Joining_Date, Annual_Income)
VALUES
('Amit Khan', 'XYZ Digital', 'Kolkata', '2019-10-06', 350000),
('Shreetama Pal', 'ABC Corp.', 'Kolkata', '2018-12-16', 500000),
('Aniket Sharma', 'PQR Soln.', 'Delhi', '2020-01-11', 300000),
('Maitree Jana', 'XYZ Digital', 'Kolkata', '2019-05-01', 400000),
('Priyanka Ojha', 'ABC Corp.', 'Delhi', '2019-02-13', 350000),
('Sayani Mitra', 'XYZ Digital', 'Kolkata', '2019-09-15', 320000),
('Nitin Dey', 'PQR Soln.', 'Delhi', '2019-10-06', 250000),
('Sujata Samanta', 'PQR Soln.', 'Kolkata', '2020-10-06', 350000),
('Sudip Majhi', 'ABC Corp.', 'Delhi', '2018-10-30', 600000),
('Sanjoy Kohli', 'XYZ Digital', 'Delhi', '2019-04-18', 450000);
要验证使用以下命令如下 -
Select * from EmployeeDetails;
输出 :
EMPLOYEE_ID | EMPLOYEE_NAME | WORKING_AT | WORK_LOCATION | JOINING_DATE | ANNUAL_INCOME |
---|---|---|---|---|---|
1 | Amit Khan | XYZ Digital | Kolkata | 2019-10-06 | 350000 |
2 | Shreetama Pal | ABC Corp. | Kolkata | 2018-12-16 | 500000 |
3 | Aniket Sharma | PQR Soln. | Delhi | 2020-01-11 | 300000 |
4 | Maitree Jana | XYZ Digital | Kolkata | 2019-05-01 | 400000 |
5 | Priyanka Ojha | ABC Corp. | Delhi | 2019-02-13 | 350000 |
6 | Sayani Mitra | XYZ Digital | Kolkata | 2019-09-15 | 320000 |
7 | Nitin Dey | PQR Soln. | Delhi | 2019-10-06 | 250000 |
8 | Sujata Samanta | PQR Soln. | Kolkata | 2020-10-06 | 350000 |
9 | Sudip Majhi | ABC Corp. | Delhi | 2018-10-30 | 600000 |
10 | Sanjoy Kohli | XYZ Digital | Delhi | 2019-04-18 | 450000 |
现在我们将从 EmployeeDetails 表中找到所有员工公司的年收入的 BIT_XOR。
SELECT Working_At, BIT_XOR(Annual_Income) AS BITXORINCOME
FROM EmployeeDetails
Group By Working_At;
输出 :
WORKING_AT | BITXORINCOME |
---|---|
XYZ Digital | 94816 |
ABC Corp. | 774608 |
PQR Soln. | 136256 |
示例 2 :
现在我们将从 EmployeeDetails 表中找到所有员工位置明智的年收入的 BIT_XOR。
SELECT Work_Location, BIT_XOR(Annual_Income) AS BITORINCOME
FROM EmployeeDetails
Group By Work_Location;
输出 :
WORK_LOCATION | BITXORINCOME |
---|---|
Kolkata | 350624 |
Delhi | 912976 |
示例 3 :
首先创建一个 StudentMarks 表 -
CREATE TABLE StudentMarks (
StudentId INT AUTO_INCREMENT,
StudentName VARCHAR(100) NOT NULL,
Class VARCHAR(20) NOT NULL,
Roll INT NOT NULL,
Sub1Mark INT NOT NULL,
Sub2Mark INT NOT NULL,
Sub3Mark INT NOT NULL,
TotalMarks INT NOT NULL,
PRIMARY KEY(StudentId)
);
向表中插入数据——
INSERT INTO StudentMarks
(StudentName, Class, Roll, Sub1Mark, Sub2Mark, Sub3Mark, TotalMarks)
VALUES
('Amit Jana', 'V', 10100, 85, 80, 95, 260),
('Labanya Mallick', 'VI', 11000, 81, 89, 95, 265),
('Virat Sharma', 'VI', 12000, 75, 83, 90, 248),
('Sayani Samanta', 'V', 13000, 95, 90, 99, 284),
('Riyanka Panda', 'V', 14000, 70, 87, 88, 245),
('Ritika Shah', 'VI', 15000, 78, 89, 90, 257);
要验证使用以下命令如下 -
SELECT * FROM StudentMarks;
输出 :
STUDENTID | STUDENTNAME | CLASS | ROLL | SUB1MARK | SUB2MARK | SUB3MARK | TOTALMARKS |
---|---|---|---|---|---|---|---|
1 | Amit Jana | V | 10100 | 85 | 80 | 95 | 260 |
2 | Labanya Mallick | VI | 11000 | 81 | 89 | 95 | 265 |
3 | Virat Sharma | VI | 12000 | 75 | 83 | 90 | 248 |
4 | Sayani Samanta | V | 13000 | 95 | 90 | 99 | 284 |
5 | Riyanka Panda | V | 14000 | 70 | 87 | 88 | 245 |
6 | Ritika Shah | VI | 15000 | 78 | 89 | 90 | 257 |
现在我们将从 StudentMarks 表中找到所有学生班级的总分的 BIT_XOR。
SELECT Class, BIT_XOR(TotalMarks) AS BITXORMARKS
FROM StudentMarks
Group By Class;
输出 :
CLASS | BITXORMARKS |
---|---|
V | 237 |
VI | 240 |