📜  程序找到一条线的斜率

📅  最后修改于: 2021-04-27 22:35:32             🧑  作者: Mango

给定两个坐标,找到一条直线的斜率。
例子:

Input  : x1 = 4, y1 = 2, 
         x2 = 2, y2 = 5 
Output : Slope is -1.5

方法:要计算一条线的斜率,您只需要从该线开始计算两个点,即(x1,y1)和(x2,y2)。用于从两个点计算斜率的公式为:

下面是上述方法的实现:

c++
// C program for slope of line
#include 
using namespace std;
 
// function to find the slope of a straight line
float slope(float x1, float y1, float x2, float y2)
{
    return (y2 - y1) / (x2 - x1);
}
 
// driver code to check the above function
int main()
{
    float x1 = 4, y1 = 2;
    float x2 = 2, y2 = 5;
    cout << "Slope is: "
         << slope(x1, y1, x2, y2);
    return 0;
}


Java
// Java program for slope of line
import java.io.*;
 
class GFG {
    static float slope(float x1, float y1,
                       float x2, float y2)
    {
        return (y2 - y1) / (x2 - x1);
    }
    public static void main(String[] args)
    {
        float x1 = 4, y1 = 2;
        float x2 = 2, y2 = 5;
        System.out.println("Slope is " +
                    slope(x1, y1, x2, y2));
    }
}


Python
# Python program for slope of line
def slope(x1, y1, x2, y2):
    return (float)(y2-y1)/(x2-x1)
 
# driver code   
x1 = 4
y1 = 2
x2 = 2
y2 = 5
print "Slope is :", slope(x1, y1, x2, y2)


C#
// C# program for slope of line
using System;
 
class GFG
{
    static float slope(float x1, float y1,
                       float x2, float y2)
    {
        return (y2 - y1) / (x2 - x1);
    }
     
    // Driver code
    public static void Main()
    {
        float x1 = 4, y1 = 2;
        float x2 = 2, y2 = 5;
        Console.WriteLine("Slope is " +
                    slope(x1, y1, x2, y2));
    }
}
 
// This code is contributed by vt_m.


PHP


Javascript


输出:

Slope is: -1.5

时间复杂度: O(1)

辅助空间: O(1)