镜头的力量
编写程序来确定镜片的光焦度。
镜片的力量是它弯曲光线的能力。对于凸透镜,会聚能力由光焦度定义,而在凹透镜中,则由发散能力定义。屈光度 (D) 是衡量镜片屈光度的单位。
功率定义为焦距的倒数,以米为单位。
D = ( 1 / F )
这里,D 是屈光度的幂,
F是以米为单位的焦距。
例子:
Input : F = 2
Output : D = 0.5
Input : F = 0.2
Output : D = 5
C++
// C++ program to determine
// the power of a lens
#include
using namespace std;
// function to determine the
// power of a lens
float power(float focal_length)
{
return (1 / focal_length);
}
// driver function
int main()
{
float focal_length = 2;
cout << "The power of the lens in diopter is "
<< power(focal_length);
return 0;
}
Java
// Java program to determine
// the power of a lens
import java.io.*;
class GFG
{
// function to determine the
// power of a lens
static float power(float focal_length)
{
return (1 / focal_length);
}
// Driver code
public static void main (String[] args)
{
float focal_length = 2;
System.out.println("The power of the lens in diopter is "
+ power(focal_length));
}
}
// This code is contributed by Gitanjali.
Python3
# Python3 program to determine
# the power of a lens
# function to determine
# the power of a lens
def power( focal_length ) :
return ( 1 / focal_length )
# driver function
focal_length = 2 ;
print ( "The power of the lens in diopter is ", end = "")
print (power(focal_length) )
C#
// C# program to determine
// the power of a lens
using System;
class GFG
{
// function to determine the
// power of a lens
static float power(float focal_length)
{
return (1 / focal_length);
}
// Driver code
public static void Main ()
{
float focal_length = 2;
Console.WriteLine("The power of the lens in diopter is "
+ power(focal_length));
}
}
// This code is contributed by vt_m.
PHP
Javascript
输出:
The power of the lens in diopter is 0.5
资源:
http://www.bbc.co.uk/bitesize/intermediate2/physics/waves_and_optics/power_of_lens/revision/1/