PYGLET – 创建文件位置

在本文中，我们将看到如何在Python的 PYGLET 模块中创建文件位置对象。 Pyglet 易于使用但功能强大的库，用于开发视觉丰富的 GUI 应用程序，如游戏、多媒体等。窗口是占用操作系统资源的“重量级”对象。 Windows 可能显示为浮动区域，也可以设置为填充整个屏幕（全屏）。为了创建文件位置对象，我们使用 pyglet 的资源模块。该模块允许应用程序指定资源的搜索路径。相对路径被认为是相对于应用程序的 __main__ 模块。 ZIP 文件可以出现在路径上；他们将在里面被搜查。
我们可以在下面给出的命令的帮助下创建一个窗口对象

# creating a window
window = pyglet.window.Window(width, height, title)

In order to create window we use FileLocation method with the pyglet.resource
Syntax : resource.FileLocation(path)
Argument : It takes string as argument
Return : It returns FileLocation object

编程需要懂一点英语

下面是实现

Python3

# importing pyglet module
import pyglet
import pyglet.window.key as key
   
# width of window
width = 500
   
# height of window
height = 500
   
# caption i.e title of the window
title = "Geeksforgeeks"
   
# creating a window
window = pyglet.window.Window(width, height, title)
   
# text 
text = "Welcome to GeeksforGeeks"
  
# creating label with following properties
# font = cooper
# position = 250, 150
# anchor position = center
label = pyglet.text.Label(text,
                          font_name ='Cooper',
                          font_size = 16,
                          x = 250, 
                          y = 150,
                          anchor_x ='center', 
                          anchor_y ='center')
 
 
# creating a batch
batch = pyglet.graphics.Batch()
 
# loading geeksforgeeks image
image = pyglet.image.load('gfg.png')
 
 
# creating sprite object
# it is instance of an image displayed on-screen
sprite = pyglet.sprite.Sprite(image, x = 200, y = 230)
   
# on draw event
@window.event
def on_draw():
       
    # clear the window
    window.clear()
       
    # draw the label
    label.draw()
     
    # draw the image on screen
    sprite.draw()
       
# key press event    
@window.event
def on_key_press(symbol, modifier):
   
    # key "C" get press
    if symbol == key.C:
         
        # printing the message
        print("Key : C is pressed")
         
# image for icon
img = image = pyglet.resource.image("gfg.png")
 
# setting image as icon
window.set_icon(img)
 
# creating a file location object
file = pyglet.resource.FileLocation("E:/btech / certi/")
 
# showing file with the help of label
label.text = str(file)
    
# start running the application
pyglet.app.run()

输出：