📜  Java中的 LinkedList element() 方法及示例

📅  最后修改于: 2022-05-13 01:54:32.061000             🧑  作者: Mango

Java中的 LinkedList element() 方法及示例

Java.util.LinkedList类的element()方法检索但不删除此列表的头部(第一个元素)。

句法:

public E element()

返回值:此方法返回此列表的头部

以下是说明element()方法的示例

示例 1:

// Java program to demonstrate
// element() method
// for Integer value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv) throws Exception
    {
        try {
  
            // creating object of LinkedList
            LinkedList list = new LinkedList();
  
            // add some elements to list
            list.add(10);
            list.add(20);
            list.add(30);
  
            // print the linked list
            System.out.println("LinkedList : " + list);
  
            // getting the head of list
            // using element() method
            int value = list.element();
  
            // print the head of list
            System.out.println("Head of list : " + value);
        }
  
        catch (NullPointerException e) {
  
            System.out.println("Exception thrown : " + e);
        }
    }
}
输出:
LinkedList : [10, 20, 30]
Head of list : 10

示例 2:

// Java program to demonstrate
// element() method
// for String value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv) throws Exception
    {
        try {
  
            // creating object of LinkedList
            LinkedList list = new LinkedList();
  
            // add some elements to list
            list.add("A");
            list.add("B");
            list.add("C");
  
            // print the linked list
            System.out.println("LinkedList : " + list);
  
            // getting the head of list
            // using element() method
            String value = list.element();
  
            // print the head of list
            System.out.println("Head of list : " + value);
        }
  
        catch (NullPointerException e) {
  
            System.out.println("Exception thrown : " + e);
        }
    }
}
输出:
LinkedList : [A, B, C]
Head of list : A