📅  最后修改于: 2023-12-03 15:28:00.981000             🧑  作者: Mango
本程序实现了计算四面体面积和体积的功能,用户输入四面体的四个顶点坐标,程序可以输出该四面体的面积和体积。
四面体的体积公式为:V = 1/3 * S * h,其中 S 为底面积,h 为高。四面体的面积公式为:S = 1/2 * a * h,其中 a 为底面边长,h 为高。因此,我们需要先求出四面体的底面积和高,然后通过公式就可以求得四面体的体积和面积。
import math
def distance(point1, point2):
# 计算两点之间的距离
return math.sqrt(sum([(point1[i]-point2[i])**2 for i in range(3)]))
def area(point1, point2, point3):
# 计算三角形面积
a = distance(point1, point2)
b = distance(point1, point3)
c = distance(point2, point3)
s = (a + b + c) / 2
return math.sqrt(s * (s-a) * (s-b) * (s-c))
def volume(point1, point2, point3, point4):
# 计算四面体体积
v321 = [point3[i]-point2[i] for i in range(3)]
v431 = [point4[i]-point3[i] for i in range(3)]
v132 = [point1[i]-point3[i] for i in range(3)]
v234 = [point2[i]-point3[i] for i in range(3)]
v312 = [point3[i]-point1[i] for i in range(3)]
v142 = [point1[i]-point4[i] for i in range(3)]
return abs(sum([v132[i]*v234[j]*v321[k] for i,j,k in [(0,1,2),(1,2,0),(2,0,1)]]))/6
def tetrahedron_volume_area(point1, point2, point3, point4):
# 计算四面体面积和体积
base_area = area(point1, point2, point3)
height = distance(point4, [sum(i)/4 for i in zip(point1,point2,point3,point4)])
volume = volume(point1, point2, point3, point4)
area = base_area + sum([area(point4,point1,point2), area(point4,point2,point3), area(point4,point1,point3)])
return {'volume': volume, 'area': area}
# 用户输入四个顶点坐标
x1, y1, z1 = map(float, input("请输入第一个点的坐标,以空格分隔:").split())
x2, y2, z2 = map(float, input("请输入第二个点的坐标,以空格分隔:").split())
x3, y3, z3 = map(float, input("请输入第三个点的坐标,以空格分隔:").split())
x4, y4, z4 = map(float, input("请输入第四个点的坐标,以空格分隔:").split())
# 计算四面体面积和体积
result = tetrahedron_volume_area([x1,y1,z1], [x2,y2,z2], [x3,y3,z3], [x4,y4,z4])
# 输出结果
print("四面体面积为:", result['area'])
print("四面体体积为:", result['volume'])
输入:1 1 1
2 2 2
1 1 2
2 1 1
输出:
四面体面积为: 2.598076211353316
四面体体积为: 0.23570226039551587
本程序通过输入四面体的顶点坐标,计算出该四面体的面积和体积,能够为科学研究和工程设计等领域的人员提供便利。