📅  最后修改于: 2023-12-03 14:55:46.981000             🧑  作者: Mango
在编写代码时,我们经常会遇到需要检查数组上两个给定类型的求反计数是否相等的情况。这个问题可以写成一个函数,函数输入为一个数组和两个类型,输出为一个布尔值,表示两个类型的求反计数是否相等。下面是一个Python的实现:
def check_count_equal(array, type_1, type_2):
"""
Check if the count of two given types are equal when inverted in the array.
:param array: The array to check.
:param type_1: The first type to invert and count.
:param type_2: The second type to invert and count.
:return: True if the count of the two types are equal when inverted. False otherwise.
"""
type_1_count = 0
type_2_count = 0
for item in array:
if isinstance(item, type_1):
type_1_count += 1
elif isinstance(item, type_2):
type_2_count += 1
return type_1_count == type_2_count
这个函数接收三个参数:一个数组,以及两个需要检查的类型(type_1和type_2)。它遍历整个数组,计算两个类型各自的求反个数(即不是该类型的元素个数),并返回两个求反个数是否相等的布尔值。这个函数可以用于检查数组上两个类型的求反计数是否相等,例如:
>>> array = [1, 'a', 2.5, 'b', 3, 'c']
>>> check_count_equal(array, int, str)
True
这会返回True,因为数组中有三个整数和三个字符串,它们的求反个数都是相等的。
在此例引入类(class)来使代码更容易维护。使用 typ as Type,type_1_count 和 type_2_count 变成 two_counts[Type] 的字典形式存储,在循环中直接取数据,可使得对于更多 type 数量的扩展更为容易:
from typing import List, Type, Dict
class ArrayCountChecker:
@staticmethod
def check_counts_equal(array: List, type_1: Type, type_2: Type) -> bool:
"""
Check if the count of two given types are equal when inverted in the array.
:param array: The array to check.
:param type_1: The first type to invert and count.
:param type_2: The second type to invert and count.
:return: True if the count of the two types are equal when inverted. False otherwise.
"""
two_counts: Dict[Type, int] = {type_1: 0, type_2: 0}
for item in array:
for Type in two_counts:
if isinstance(item, Type):
two_counts[Type] += 1
return two_counts[type_1] == two_counts[type_2]
使用示例代码:
>>> array = [1, 'a', 2.5, 'b', 3, 'c']
>>> ArrayCountChecker.check_counts_equal(array, int, str)
True
与之前相同,返回 True。
这样的好处是:
以上是该函数的介绍和实现,通过这个函数,您可以轻松地检查一个数组上两个给定类型的求反计数是否相等。