使用给定的频率列表生成列表

给定一个列表，任务是从给定列表中生成另一个包含从0 到 n的数字的列表，其每个元素是生成列表中数字的频率。

Input: freq = [1, 4, 3, 5]
Output: [0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3]

Explanation:
Number = 0
Input[0] = 1 Output = [0]

Number =1
Input[1] = 4 Output = [0, 1, 1, 1, 1] (repeats 1 four times)

Number =2
Input[2] = 3  Output = [0, 1, 1, 1, 1, 2, 2, 2] (repeats 2 three times)

Number =3
Input[3] = 5  Output = [0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3] (repeats 3 five times)

以下是实现上述任务的一些方法。

方法#1：使用迭代

# Python code to generate list containing numbers from 0 to 'n'
# having frequency of no from another list
  
# List initialisation
Input = [1, 4, 3, 5]
Output = []
  
# Number initialisation
no = 0
  
# using iteration
for rep in Input:
    for elem in range(rep):
        Output.append(no)
    no += 1
  
# printing output
print(Output) 

输出：

[0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3]

方法#2：使用枚举和列表推导

# Python code to generate list containing numbers from 0 to 'n'
# having frequency of no from another list
  
# List initialisation
Input = [1, 4, 3, 5]
  
# Using enumerate and list comprehension
Output = [no for no, rep in enumerate(Input)
                     for elem in range(rep)]
  
# Printing output
print(Output) 

输出：

[0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3]

方法#3：使用枚举和链

# Python code to generate list containing numbers from 0 to 'n'
# having frequency of no from another list
  
# List initialisation
Input = [1, 4, 3, 5]
  
# Importing
from itertools import repeat, chain
  
# Using chain and enumerate
Output = list(chain.from_iterable((repeat(x, y))
                  for x, y in enumerate(Input)))
  
# Printing output
print(Output) 

输出：

[0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3]