Java中的 StrictMath hypot() 方法
根据基本几何,斜边不过是直角三角形的最长边。它是三角形的直角的对边。为了找到直角三角形的斜边的长度,应用了勾股定理。根据这个定理,给定长度为 p 和 b 的三角形的两条垂直边,斜边可以通过以下公式找到 .
Java.lang.StrictMath.hypot()是 StrictMath 类的内置方法,用于获取给定两侧或参数的斜边或平方和的平方根,即 .该方法排除了所有中间溢出和下溢。它产生了一些特殊的结果:
- 当num1或num2中的任何一个为无穷大时,该方法返回正无穷大。
- 当任何一个参数都是 NAN 并且两个参数都不是无限时,它返回 NAN。
句法:
public static double hypot(double num1, double num2)
参数:该方法接受两个Double类型的参数:
- num1:这是第一个值或任何一侧。
- num2:这是第二个值或另一边。
返回值:方法返回即斜边的长度。
例子 :
Input: num1 = 3
num2 = 4
Output: 5.0
下面的程序说明了Java.lang.StrictMath.hypot() 方法:
方案一:
java
// Java program to illustrate the
// Java.lang.StrictMath.hypot() Method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 11, num2 = 13.8;
// It returns the hypotenuse
double hypotlen = StrictMath.hypot(num1, num2);
System.out.println("Length of hypotenuse of side "
+ num1 + " & " + num2 + " = " + hypotlen);
}
}
java
// Java program to illustrate the
// Java.lang.StrictMath.hypot() Method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = -54, num2 = -24.8;
// It returns the hypotenuse
double hypotlen = StrictMath.hypot(num1, num2);
System.out.println("Length of hypotenuse of side "
+ num1 + " & " + num2 + " = " + hypotlen);
}
}
java
// Java program to illustrate the
// Java.lang.StrictMath.hypot() Method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 4;
double positive_Infinity = Double.POSITIVE_INFINITY;
double negative_Infinity = Double.NEGATIVE_INFINITY;
double nan = Double.NaN;
// When 1 or more argument is NAN
double hypotlen = StrictMath.hypot(nan, num1);
System.out.println("Hypotenuse length = " + hypotlen);
// When both arguments are infinity
hypotlen = StrictMath.hypot(positive_Infinity,
negative_Infinity);
System.out.println("Hypotenuse length = " + hypotlen);
}
}
输出:
Length of hypotenuse of side 11.0 & 13.8 = 17.647662734764623
方案二:
Java
// Java program to illustrate the
// Java.lang.StrictMath.hypot() Method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = -54, num2 = -24.8;
// It returns the hypotenuse
double hypotlen = StrictMath.hypot(num1, num2);
System.out.println("Length of hypotenuse of side "
+ num1 + " & " + num2 + " = " + hypotlen);
}
}
输出:
Length of hypotenuse of side -54.0 & -24.8 = 59.422554640473
方案 3:
Java
// Java program to illustrate the
// Java.lang.StrictMath.hypot() Method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 4;
double positive_Infinity = Double.POSITIVE_INFINITY;
double negative_Infinity = Double.NEGATIVE_INFINITY;
double nan = Double.NaN;
// When 1 or more argument is NAN
double hypotlen = StrictMath.hypot(nan, num1);
System.out.println("Hypotenuse length = " + hypotlen);
// When both arguments are infinity
hypotlen = StrictMath.hypot(positive_Infinity,
negative_Infinity);
System.out.println("Hypotenuse length = " + hypotlen);
}
}
输出:
Hypotenuse length = NaN
Hypotenuse length = Infinity