numpy.ma.notmasked_contiguous函数| Python
numpy.ma.notmasked_contiguous()
函数在给定轴的掩码数组中查找连续的未掩码数据。
Syntax : numpy.ma.notmasked_contiguous(arr, axis = None)
Parameters :
arr : [array_like] The input array.
axis : [int, optional] Axis along which to perform the operation. Default is None.
Return : [list] A list of slices (start and end indexes) of unmasked indexes in the array. If the input is 2d and axis is specified, the result is a list of lists.
代码#1:
# Python program explaining
# numpy.ma.notmasked_contiguous() function
# importing numpy as geek
# and numpy.ma module as ma
import numpy as geek
import numpy.ma as ma
arr = geek.arange(12).reshape((3, 4))
mask = geek.zeros_like(arr)
mask[1:, :-1] = 1; mask[0, 1] = 1; mask[-1, 0] = 0
ma = geek.ma.array(arr, mask = mask)
gfg = geek.ma.notmasked_contiguous(ma)
print (gfg)
输出 :
[slice(0, 1, None), slice(2, 4, None), slice(7, 9, None), slice(11, 12, None)]
代码#2:
# Python program explaining
# numpy.ma.notmasked_contiguous() function
# importing numpy as geek
# and numpy.ma module as ma
import numpy as geek
import numpy.ma as ma
arr = geek.arange(12).reshape((3, 4))
mask = geek.zeros_like(arr)
mask[1:, :-1] = 1; mask[0, 1] = 1; mask[-1, 0] = 0
ma = geek.ma.array(arr, mask = mask)
gfg = geek.ma.notmasked_contiguous(ma, axis = 1)
print (gfg)
输出 :
[[slice(0, 1, None), slice(2, 4, None)], [slice(3, 4, None)], [slice(0, 1, None), slice(3, 4, None)]]