Java中的堆栈搜索()方法
Java中的Java .util.Stack.search( Object element ) 方法用于在堆栈中搜索元素并获取其与顶部的距离。此方法从 1 开始计数位置,而不是从 0 开始。位于堆栈顶部的元素被认为位于位置 1。如果存在多个元素,则最接近顶部的元素的索引被退回。如果成功找到元素,则该方法返回其位置,如果元素不存在,则返回 -1。
句法:
STACK.search(element)
参数:该方法接受一个参数元素,该元素是指需要在堆栈中搜索的元素。
返回值:如果在堆栈中成功找到该元素的位置(以计数为基数1),则该方法返回该元素的位置,否则返回-1。
下面的程序说明了Java.util.Stack.search() 方法的工作:
方案一:
// Java code to demonstrate search() method
import java.util.*;
public class Stack_Demo {
public static void main(String[] args)
{
// Creating an empty Stack
Stack STACK = new Stack();
// Stacking strings
STACK.push("Geeks");
STACK.push("4");
STACK.push("Geeks");
STACK.push("Welcomes");
STACK.push("You");
// Displaying the Stack
System.out.println("The stack is: " + STACK);
// Checking for the element "4"
System.out.println("Does the stack contains '4'? "
+ STACK.search("4"));
// Checking for the element "Hello"
System.out.println("Does the stack contains 'Hello'? "
+ STACK.search("Hello"));
// Checking for the element "Geeks"
System.out.println("Does the stack contains 'Geeks'? "
+ STACK.search("Geeks"));
}
}
输出:
The stack is: [Geeks, 4, Geeks, Welcomes, You]
Does the stack contains '4'? 4
Does the stack contains 'Hello'? -1
Does the stack contains 'Geeks'? 3
方案二:
// Java code to demonstrate search() method
import java.util.*;
public class Stack_Demo {
public static void main(String[] args)
{
// Creating an empty Stack
Stack STACK = new Stack();
// Stacking int values
STACK.push(8);
STACK.push(5);
STACK.push(9);
STACK.push(2);
STACK.push(4);
// Displaying the Stack
System.out.println("The stack is: " + STACK);
// Checking for the element 9
System.out.println("Does the stack contains '9'? "
+ STACK.search(9));
// Checking for the element 10
System.out.println("Does the stack contains '10'? "
+ STACK.search(10));
// Checking for the element 11
System.out.println("Does the stack contains '11'? "
+ STACK.search(11));
}
}
输出:
The stack is: [8, 5, 9, 2, 4]
Does the stack contains '9'? 3
Does the stack contains '10'? -1
Does the stack contains '11'? -1