TCS安置纸| MCQ 9

这是用于能力倾向准备的TCS模型放置论文。这份安置文件将涵盖在TCS招聘活动中提出的才能问题，并且还将严格遵循在TCS面试中提出的问题模式。建议解决以下每个问题，以增加清除TCS面试的机会。

1. 当a + b除以12时，余数为8，而当a – b除以12时，余数为6。如果a> b，则ab除以6时余数是多少?
   a)3
   b)1
   c)5
   d)4

   Answer: b) 1

   Solution:
   According to the question,
   a + b = 12k + 8
   => $$(a+b)^2 = 144k^2 + 64 + 192k$$
   a – b = 12l + 6
   => $$(a-b)^2 = 144l^2 + 36 - 144l$$
   Subtracting both the equations we get,
   ab = $$36(k^2 - l^2) + 48k - 36l + 7$$
   Now all the terms of ab is divisible by 6, except 7. So the remainder left is 1.

2. 共有26个问题。对于每个错误答案，将扣除5分，并为每个正确答案加8分。假设所有问题都已回答，并且分数为0，那么正确回答了多少个问题?
   a)12
   b)10
   c)11
   d)13

   Answer: b) 10

   Solution:
   This can be easily solved using hit and trial method.
   Let’s consider the first option. If 12 questions in all are answered correctly, then the total score = 12 * 8 = 96 marks.
   If 12 questions are answered correctly, then 14 questions were wrongly answered. So total deductions = 14 * 5 = 70 marks.
   So total score = 96 – 70 = 26 which is not correct.
   Let’s consider the second option. If 10 questions in all are answered correctly, then the total score = 10 * 8 = 80 marks.
   If 10 questions are answered correctly, then 16 questions were wrongly answered. So total deductions = 16 * 5 = 80 marks.
   So total score = 80 – 80 = 0
   Hence 10 is the correct option.

3. 有一天，拉梅什(Ramesh)距离家乡晚了30分钟，以比平时慢25％的速度行驶，但比家乡市场晚了50分钟到达市场。 Ramesh通常需要几分钟的时间才能在家中进入市场?
   a)20
   b)40
   c)60
   d)80

   Answer: a) 60

   Solution:
   Let the usual speed of Ramesh be ‘s’
   Let the distance between home and market be ‘d’
   So usual time took = d/s
   Time took on that particular day = d/(3s/4)
   So according to the question,
   d/s(4/3 – 1) = 20
   or, d/s = 60

4. 三个容器A，B和C分别以1：5、3：5、5：7的比例混合牛奶和水。如果容器的容量比例为5：4：5，并且将三个容器都混合在一起，则求出牛奶与水的比例。
   a)54：115
   b)53：113
   c)53：115
   d)54：113

   Answer: c) 53:115

   Solution:
   Using the weighted average formula we can calculate the weight of milk,
   => [5*(1/6) + 4*(3/8) + 5*(5/12)]/(5+4+5) = 53/168
   So weight of water = 168 – 53 = 115
   So the ratio of milk to water = 53:115

5. 阿曼参加了橙色比赛。在比赛中，将20个橙子排成4米，每条橙子距起点24米。阿曼必须一次将橙子带回起点。他要带回所有橘子要走多远?
   a)1440
   b)2440
   c)1240
   d)2480

   Answer: d) 2480 

   Solution:
   Since every orange is placed at a difference of 4 meters and the first potato is placed at 24 meters from the starting position. Every orange is placed at 24m, 28m, 32m, 36m, ….20 terms.
   Now to bring ever orange one at a time, Aman needs to cover the double of the distance = 48, 56, 64, …20 terms.
   So putting the values in the sum of AP formula, a = 48, d= 8, n = 20.
   Total distance travelled = 20/2 [2 * 48 + (20-1)*8]
   = 2480 meters

6. 有两副牌，每副牌包含20张牌，上面写着从1到20的数字。从每个牌组中随机抽取一张牌，得到数字x和y。log x + log y是正整数的概率是多少。 (日志以10为底。)
   a)7/400
   b)29/100
   c)3/200
   d)1/80

   Answer: a) 7/400

   Solution:
   We know that log x + log y = log xy
   for log xy to be positive, we have the following choices:
   (1, 10), (10, 1), (10, 10), (5, 20), (20, 5), (2, 5), (5, 2)
   So the probability = 7/400

7. 有一个可容纳10人的圆锥形帐篷。每个人需要6平方米的空间才能坐下，呼吸30立方米的空气。圆锥的高度是多少?
   a)72米
   b)15 m
   c)37.5 m
   d)155 m

   Answer: b) 15 m

   Solution:
   All the persons are to sit on the ground forming the base of the cone.
   Total base covered = pi * $$r^2$$ = 6*10 = 60 sq-meter.
   The total volume of the tent will be equal to the total air to breathe by the 10 people = 30*10 = 300 cubic meter
   So, 1/3(pi * $$r^2$$ * h) = 300
   => h = 15 meters.

8. 找到143的最大功效，可以除以125！确切地。
   a)11
   b)8
   c)9
   d)7

   Answer: c) 9

   Solution:
   We can write 143 = 11 × 13.
   So the highest power of 13 should be considered in 125!, which is 9 (13 * 9 = 117)
   The highest power of 11 in 125! is 12 (11 * 11 = 121 and remaining 1).
   That means, 125! = 11^12×13^9×…
   So only nine 13’s are available. So we can form only nine 143’s in 125!. So maximum power of 143 is 9.

9. 一辆汽车从下午6:00开始。从起点以18 m / s的速度到达目的地。在那里，它等待了40分钟，然后以28 m / s的速度返回。找到到达目的地所花费的时间。
   a)下午9:44
   b)下午8:32
   c)晚上7:30
   d)晚上9:30

   Answer: a) 9:44 pm

   Solution:
   Let the distance covered be D m
   The time to cover the starting distance = D/18 secs.
   The time taken for the reverse journey = D/28 secs.
   According to the quesiton,
   D/18 – D/28 = (40 × 60)
   On solving this we get,
   D = 2400 × 252/5 = 120960 m
   No the total time taken = (D/18) + (D/28) + 2400 = 13440 seconds
   = 3 hours and 44 minutes
   Therefore, the bus reaches back at 9:44 PM

10. 房屋的价值每年贬值，是其年初初值的3/4。如果踏板车的初始值为Rs。 40，000。3年后的价值是多少?
    a)卢比。 19000
    b)卢比。 16875
    c)卢比。 17525
    d)卢比。 18000

    Answer:  b) 16875

    Solution:
    This is the question of succession depreciation.
    the starting amount = Rs. 40000
    This reduces by 3/4 th of its initial value every year = (40, 000) * (3/4)^3 = 16875