这是用于Cognizant技术解决方案面试的能力准备的模型介绍文件。这份安置文件将涵盖在CTS招聘活动中提出的才能问题,并且还将严格遵循在CTS面试中提出的问题模式。建议解决以下每个问题,以增加清除CTS面试的机会。
- 可以切合三个分别为6厘米,8厘米和10厘米的边缘立方体,而不会损失金属到一个立方体中。新立方体的边缘将是:
a)16厘米
b)14厘米
c)12厘米
d)8厘米Answer: c) 12 cm
Solution:
Since the cube is melted so the volume of the new cube must be the same.
Volume of new cube = Volume of cube 1 + cube 2 + cube 3 = 63 + 83 + 103 = 216 + 512 + 1000
a^3 = 1728,
a = (1728)^(1/3) = 12 - 芒果价格降低20%,使农民能够以12卢比的价格购买更多12芒果。 15.那么,降价前16芒果的价格是多少?
a)卢比。 9
b)卢比。 7
c)卢比。 5
d)卢比。 6Answer: c) Rs. 5
Solution:
We know that
Price * Consumption = Expenditure
and, Consumption = Expenditure Price
So,
(15 / 8x) – (15 / x) = 12
x = (15 * 2) / (12 * 8)
For 16 Mangoes = [(15 * 2) / (12 * 8)] * 16 = 5 (answer) - 阿曼(Aman)在10小时内完成了一个旅程。他上半部分以21 km / hr的速度旅行,下半部分以24 km / hr的速度旅行。查找以公里为单位的总行程。
a)220公里
b)234公里
c)230公里
d)224公里Answer: d) 224 km
Solution:
According to the question,
((1/2)x)/21 + ((1/2)x)/24 = 10
Solving this equation we get 15x = 168 * 20
Further x = (168 * 20)/15 = 224 km. - 有两个闹钟分别以50秒和48秒的间隔响铃。如果他们在中午12点第一次一起发出哔哔声,他们将在什么时候再次发出哔哔声?
a)下午12:10
b)下午12:20
c)下午12:11
d)下午12:12Answer: b) 12:20 PM
Solution:
This can be found by finding the LCM of 48 and 50.
They will ring together after,
LCM of 48 and 50 secs.
48 = 2*2*2*2*3;
50 = 2*5*5;
So, LCM = 2*2*2*2*3*5*5 = 1200 secs = 20 min.
Therefore, they will beep together at 12:20 PM next. - Ram以Rs的价格购买了20个玩具。每打375。他以卢比的价格卖掉了每一个。 33.他的利润百分比是多少?
a)5.6%
b)4.5%
c)3.5%
d)6.5%Answer: a) 5.6 %
Solution:
Let’s find the cost price of 1 toy = 375 / 12 = 31.25 rupees.
Now, SP of 1 toy = 33 rupees.
So, Gain = SP – CP = (33 – 31.25) = Rs. 1.75
and Profit % = 1.75 / 31.25 * 100 = 5.6 % - 水龙头可以在4小时内装满一个水箱,而水龙头可以在9小时内将其装满。如果两个水龙头同时打开,那么储水箱要多少时间才能装满?
a)7小时
b)7.1小时
c)7.2小时
d)7.3小时Answer: 7.2 hours
Solution:
So according to the question,
1/4 th of the cistern can be filled in one hour
1/9 th of the cistern can be emptied in 1 hour
Therfore, net filled in 1 hour = 1/4 – 1/9 = 5/36
So cistern that can be filled in 36/5 hours = 7.2 hours - “ INHALE”一词的字母可以用几种不同的方式排列吗?
a)650种方式
b)360种方式
c)120路
d)720种方式Answer: d) 720 ways
Solution:
There are 6 letters in the word and no letters are repeated.
So, the 6 letters can be arranged in 6! ways = 720 ways. - 在一次会议上,有12人。一个国家的所有人与另一国家的所有代表握手。找出可能的握手次数?
a)66
b)288
c)144
d)234Answer: a) 66
Solution:
Total number of handshakes = n(n-1)/2=(12 * 11)/2 = 66 - 减少8时可被21、27、33和55整除的最小数字是多少?
a)1490
b)10405
c)15490
d)以上都不是Answer: d) none of the above
Solution:
We need to find the LCM of the given numbers,
LCM of 21, 27, 33, and 55 = 10395
So we need to add an extra 5 = 10403 (answer) - 某个联赛中有8支橄榄球队,而每支球队只对其他一支球队进行一次比赛。如果每场比赛由2支球队进行,那么总比赛数是多少?
a)15
b)16
c)64
d)28Answer: d) 28
Solution:
Since there are 8 teams, so each pair will pay a match = 8C2 = 28 matches.