unordered_multimap :: reserve()是C++ STL中的内置函数,该函数将容器中的存储桶数(bucket_count)设置为最合适的数目,以便它至少包含n个元素。如果n大于当前的bucket_count乘以max_load_factor ,则增加容器的bucket_count并强制进行重新哈希处理。通过使用unordered_multimap容器期望的大小调用reserve ,可以避免多次重排。多次重复是由于容器大小增加而产生的,从而优化了哈希表的大小。如果n小于该值,则该函数可能无效。
句法:
unordered_multimap_name.reserve(N)
参数:该函数接受单个强制性参数N ,该参数N将所请求的元素数指定为最小容量。
返回值:该函数不返回任何内容。
下面的程序说明了上述函数:
程序1:
// C++ program to illustrate the
// unordered_multimap::reserve()
#include
using namespace std;
int main()
{
// declaration
unordered_multimap sample1, sample2;
// the sample1 size is reserved for
// the bucket to contain a minimum of
// one elements
sample1.reserve(1);
// inserts key and element
// in sample1
sample1.insert({ 10, 100 });
sample1.insert({ 50, 500 });
// inserts key and element
// in sample1
// the sample1 size is reserved for
// the bucket to contain a minimum of
// three elements
sample2.reserve(3);
sample2.insert({ 20, 200 });
sample2.insert({ 30, 300 });
sample2.insert({ 30, 150 });
cout << "The size of Sample1 is: " << sample1.size();
cout << "\nKey and Elements of Sample1 are:";
for (auto it = sample1.begin(); it != sample1.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
cout << "\n\nThe size of Sample2 is: " << sample2.size();
cout << "\nKey and Elements of Sample2 are:";
for (auto it = sample2.begin(); it != sample2.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
return 0;
}
输出:
The size of Sample1 is: 2
Key and Elements of Sample1 are:{50, 500} {10, 100}
The size of Sample2 is: 3
Key and Elements of Sample2 are:{30, 150} {30, 300} {20, 200}
程式2:
// C++ program to illustrate the
// unordered_multimap::reserve()
#include
using namespace std;
int main()
{
// declaration
unordered_multimap sample1, sample2;
// the sample1 size is reserved for
// the bucket to contain a minimum of
// one elements
sample1.reserve(1);
// inserts key and element
// in sample1
sample1.insert({ 'a', 'A' });
sample1.insert({ 'g', 'G' });
// inserts key and element
// in sample1
// the sample1 size is reserved for
// the bucket to contain a minimum of
// three elements
sample2.reserve(3);
sample2.insert({ 'b', 'B' });
sample2.insert({ 'c', 'C' });
sample2.insert({ 'd', 'D' });
cout << "The size of Sample1 is: " << sample1.size();
cout << "\nKey and Elements of Sample1 are:";
for (auto it = sample1.begin(); it != sample1.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
cout << "\n\nThe size of Sample2 is: " << sample2.size();
cout << "\nKey and Elements of Sample2 are:";
for (auto it = sample2.begin(); it != sample2.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
return 0;
}
输出:
The size of Sample1 is: 2
Key and Elements of Sample1 are:{g, G} {a, A}
The size of Sample2 is: 3
Key and Elements of Sample2 are:{d, D} {c, C} {b, B}
要从最佳影片策划和实践问题去学习,检查了C++基础课程为基础,以先进的C++和C++ STL课程基础加上STL。要完成从学习语言到DS Algo等的更多准备工作,请参阅“完整面试准备课程” 。