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📜  检查是否可以通过给定的跳转从(a,0)移至(b,0)

📅  最后修改于: 2021-06-25 22:17:18             🧑  作者: Mango

给定两个点,即(a,0)至(b,0)。任务是检查是否可以从(a,0)移至(b,0)。一个可以移动为(a,0),(a + x,0),(a + x + 1,0),(a,2 * x,0),(a,2 * x + 1,0)… …

例子:

Input: a = 3, x = 10, b = 4
Output: No

Input: a = 3, x = 2, b = 5
Output: Yes

方法:如果可能,答案是可能的

下面是上述方法的实现:

C++
// CPP program to move form
// (a, 0) to (b, 0) with given jumps
#include 
using namespace std;
  
// Function to check if it is possible
bool Move(int a, int x, int b)
{
    if ((((b - a) % x == 0) || ((b - a - 1) % x == 0) && a + 1 != b) && b >= a)
        return true;
  
    return false;
}
  
// Driver code
int main()
{
    int a = 3, x = 2, b = 7;
  
    // function call
    if (Move(a, x, b))
        cout << "Yes";
    else
        cout << "No";
}


Java
// Java program to move form 
// (a, 0) to (b, 0) with given jumps 
import java.io.*;
  
class GFG {
  
// Function to check if it is possible 
static boolean Move(int a, int x, int b) 
{ 
    if ((((b - a) % x == 0) || ((b - a - 1) % x == 0) && a + 1 != b) && b >= a) 
        return true; 
  
    return false; 
} 
  
// Driver code 
    public static void main (String[] args) {
            int a = 3, x = 2, b = 7; 
  
    // function call 
    if (Move(a, x, b)) 
        System.out.println( "Yes"); 
    else
        System.out.println( "No"); 
    }
}
//This code is contributed by shs..


Python 3
# Python 3 program to move form
# (a, 0) to (b, 0) with given jumps
  
# Function to check if it
# is possible
def Move(a, x, b):
  
    if ((((b - a) % x == 0) or 
         ((b - a - 1) % x == 0) and 
           a + 1 != b) and b >= a):
        return True
  
    return False
  
# Driver code
if __name__ == "__main__":
    a = 3
    x = 2
    b = 7
  
    # function call
    if (Move(a, x, b)):
        print("Yes")
    else:
        print("No")
  
# This code is contributed 
# by ChitraNayal


C#
// C# program to move form 
// (a, 0) to (b, 0) with given jumps 
using System;
  
class GFG 
{
  
// Function to check if it is possible 
static bool Move(int a, int x, int b) 
{ 
    if ((((b - a) % x == 0) || 
         ((b - a - 1) % x == 0) && 
           a + 1 != b) && b >= a) 
        return true; 
  
    return false; 
} 
  
// Driver code 
public static void Main () 
{
    int a = 3, x = 2, b = 7; 
  
    // function call 
    if (Move(a, x, b)) 
        Console.WriteLine( "Yes"); 
    else
        Console.WriteLine( "No"); 
}
}
  
// This code is contributed 
// by inder_verma


PHP
= $a)
        return true;
  
    return false;
}
  
// Driver code
$a = 3; $x = 2; $b = 7;
  
// function call
if (Move($a, $x, $b))
    echo "Yes";
else
    echo"No";
      
// This code is contributed 
// by anuj_67
?>


输出:
Yes

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