给定一个由不同整数arr []组成的数组,任务是找到一个具有最小和的对,并打印该和。
例子:
Input: arr[] = {1, 2, 3}
Output: 3
The pair (1, 2) will have the minimum sum pair i.e. 1 + 2 = 3
Input: arr[] = {3, 5, 6, 2}
Output: 5
方法:
- 从数组中找到最小元素,并将其存储在min中。
- 从数组中找到第二个最小元素,并将其存储在secondMin中。
- 打印min + secondMin 。
下面是上述方法的实现:
C++
// C++ program to print the sum of the minimum pair
#include
using namespace std;
// Function to return the sum of
// the minimum pair from the array
int smallest_pair(int a[], int n)
{
int min = INT_MAX, secondMin = INT_MAX;
for (int j = 0; j < n; j++) {
// If found new minimum
if (a[j] < min) {
// Minimum now becomes second minimum
secondMin = min;
// Update minimum
min = a[j];
}
// If current element is > min and < secondMin
else if ((a[j] < secondMin) && a[j] != min)
// Update secondMin
secondMin = a[j];
}
// Return the sum of the minimum pair
return (secondMin + min);
}
// Driver code
int main()
{
int arr[] = { 1, 2, 3 };
int n = sizeof(arr) / sizeof(arr[0]);
cout << smallest_pair(arr, n);
return 0;
}
Java
// Java program to print the sum
// of the minimum pair
import java .io.*;
class GFG
{
// Function to return the sum of
// the minimum pair from the array
static int smallest_pair(int[] a, int n)
{
int min = Integer.MAX_VALUE, secondMin = Integer.MAX_VALUE;
for (int j = 0; j < n; j++)
{
// If found new minimum
if (a[j] < min)
{
// Minimum now becomes second minimum
secondMin = min;
// Update minimum
min = a[j];
}
// If current element is > min and < secondMin
else if ((a[j] < secondMin) && a[j] != min)
// Update secondMin
secondMin = a[j];
}
// Return the sum of the minimum pair
return (secondMin + min);
}
// Driver code
public static void main(String[] args)
{
int[] arr = { 1, 2, 3 };
int n = arr.length;
System.out.println(smallest_pair(arr, n));
}
}
// This code is contributed
// by inder_verma
Python3
# Python3 program to print the
# sum of the minimum pair
import sys
# Function to return the sum of
# the minimum pair from the array
def smallest_pair(a, n) :
min = sys.maxsize
secondMin = sys.maxsize
for j in range(n) :
# If found new minimum
if (a[j] < min) :
# Minimum now becomes
# second minimum
secondMin = min
# Update minimum
min = a[j]
# If current element is > min
# and < secondMin
elif ((a[j] < secondMin) and
a[j] != min) :
# Update secondMin
secondMin = a[j]
# Return the sum of the minimum pair
return (secondMin + min)
# Driver code
if __name__ == "__main__" :
arr = [ 1, 2, 3 ]
n = len(arr)
print(smallest_pair(arr, n))
# This code is contributed by Ryuga
C#
// C# program to print the sum
// of the minimum pair
using System;
class GFG
{
// Function to return the sum of
// the minimum pair from the array
static int smallest_pair(int[] a, int n)
{
int min = int.MaxValue, secondMin = int.MaxValue;
for (int j = 0; j < n; j++)
{
// If found new minimum
if (a[j] < min)
{
// Minimum now becomes second minimum
secondMin = min;
// Update minimum
min = a[j];
}
// If current element is > min and < secondMin
else if ((a[j] < secondMin) && a[j] != min)
// Update secondMin
secondMin = a[j];
}
// Return the sum of the minimum pair
return (secondMin + min);
}
// Driver code
public static void Main()
{
int[] arr = { 1, 2, 3 };
int n = arr.Length;
Console.Write(smallest_pair(arr, n));
}
}
// This code is contributed
// by Akanksha Rai
PHP
min
// and < secondMin
else if (($a[$j] < $secondMin) &&
$a[$j] != $min)
// Update secondMin
$secondMin = $a[$j];
}
// Return the sum of the minimum pair
return ($secondMin + $min);
}
// Driver code
$arr = array( 1, 2, 3 );
$n = sizeof($arr);
echo smallest_pair($arr, $n);
// This code is contributed by ajit
?>
Javascript
输出:
3
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