📜  门| GATE-CS-2015(Set 1)|第54章

📅  最后修改于: 2021-06-28 19:30:54             🧑  作者: Mango

  \int_{\frac{1}{\pi}}^{\frac{2}{\pi}} cos(\frac{1/x}{x^{2}})dx = ...........
(A) 0
(B) -1
(C) 1
(D)无限答案: (B)
解释:
令f(x)为给定函数。我们假设\ [\ frac {1} {x} = z \]

区分双方,我们得到

     \[\frac{-1}{x^2} dx = dz\] Now, accordingly, the lower limit of the integral is \[ z = \frac{1}{\frac{1}{\pi}} = \pi\] and the upper limit for the integral is \[ z = \frac{1}{\frac{2}{\pi}} = \frac{\pi}{2}\] So, the given function now becomes \[ f(x)= - \int_\pi^{\frac{\pi}{2}} cos(z) dz \] \[ f(x)= \int_\frac{\pi}{2}^{\pi} cos(z) dz \] \[f(x) = sin(z) ,\] and the upper limit is π and the lower limit is π/2 So, \[f(x) = sin(\pi) - sin(\frac{\pi}{2})\] \[f(x) = 0 - 1\] \[f(x) = -1\] So, the required answer is -1.

这个问题的测验