检查三点是否共线的程序

给定三个点，检查它们是否位于直线（共线）上
例子 ：

Input : (1, 1), (1, 4), (1, 5)
Output : Yes 
The points lie on a straight line

Input : (1, 5), (2, 5), (4, 6)
Output : No 
The points do not lie on a straight line

第一种方法
如果这三个点的三角形所形成的面积为零，则这三个点位于直线上。所以我们将检查三角形形成的面积是否为零

Formula for area of triangle is : 
0.5 * [x1 * (y2 - y3) + x2 * (y3 - y1) + x3 * (y1 - y2)]

The formula is basically half of determinant
value of following.
x1 x2 x3
y1 y2 y3
1   1  1

The above formula is derived from shoelace formula.

C++

// C++ program to check if three
// points are collinear or not
// using area of triangle.
#include 
#include 
#include 
 
using namespace std;
// function to check if point
// collinear or not
void collinear(int x1, int y1, int x2,
               int y2, int x3, int y3)
{
    // Calculation the area of
    // triangle. We have skipped
    // multiplication with 0.5
    // to avoid floating point
    // computations
    int a = x1 * (y2 - y3) +
            x2 * (y3 - y1) +
            x3 * (y1 - y2);
 
    if (a == 0)
        cout << "Yes";
    else
        cout << "No";
}
 
// Driver Code
int main()
{
    int x1 = 1, x2 = 1, x3 = 1,
        y1 = 1, y2 = 4, y3 = 5;
    collinear(x1, y1, x2, y2, x3, y3);
    return 0;
}
 
// This code is contributed
// by Akanksha Rai(Abby_akku)

C

// C program to check if three
// points are collinear or not
// using area of triangle.
#include 
#include 
#include 
 
// function to check if point
// collinear or not
void collinear(int x1, int y1, int x2,
               int y2, int x3, int y3)
{
    // Calculation the area of
    // triangle. We have skipped
    // multiplication with 0.5
    // to avoid floating point
    // computations
    int a = x1 * (y2 - y3) +
            x2 * (y3 - y1) +
            x3 * (y1 - y2);
 
    if (a == 0)
        printf("Yes");
    else
        printf("No");
}
 
// Driver Code
int main()
{
    int x1 = 1, x2 = 1, x3 = 1,
        y1 = 1, y2 = 4, y3 = 5;
    collinear(x1, y1, x2, y2, x3, y3);
    return 0;
}

Java

// Java program to check if
// three points are collinear
// or not using area of triangle.
class GFG
{
     
    // function to check if
    // point collinear or not
    static void collinear(int x1, int y1, int x2,
                          int y2, int x3, int y3)
    {
         
        /* Calculation the area of
        triangle. We have skipped
        multiplication with 0.5
        to avoid floating point
        computations */
        int a = x1 * (y2 - y3) +
                x2 * (y3 - y1) +
                x3 * (y1 - y2);
     
        if (a == 0)
            System.out.println("Yes");
        else
            System.out.println("No");
    }
         
    // Driver Code
    public static void main(String args[])
    {
        int x1 = 1, x2 = 1, x3 = 1,
            y1 = 1, y2 = 4, y3 = 5;
                             
        collinear(x1, y1, x2, y2, x3, y3);
 
    }
}
 
// This code is contributed by Sam007.

Python

# Python program to check
# if three points are collinear
# or not using area of triangle.
 
# function to check if
# point collinear or not
def collinear(x1, y1, x2, y2, x3, y3):
     
    """ Calculation the area of 
        triangle. We have skipped
        multiplication with 0.5 to
        avoid floating point computations """
    a = x1 * (y2 - y3) + x2 * (y3 - y1) + x3 * (y1 - y2)
 
    if (a == 0):
        print "Yes"
    else:
        print "No"
 
# Driver Code
x1, x2, x3, y1, y2, y3 = 1, 1, 1, 1, 4, 5
collinear(x1, y1, x2, y2, x3, y3)
 
# This code is contributed
# by Sachin Bisht

C#

// C# program to check if
// three points are collinear
// or not using area of triangle.
using System;
 
class GFG
{
     
    /* function to check if
    point collinear or not */
    static void collinear(int x1, int y1, int x2,
                          int y2, int x3, int y3)
    {
         
        /* Calculation the area of 
        triangle. We have skipped
        multiplication with 0.5 to
        avoid floating point computations */
        int a = x1 * (y2 - y3) +
                x2 * (y3 - y1) +
                x3 * (y1 - y2);
     
        if (a == 0)
            Console.Write("Yes");
        else
            Console.Write("No");
    }
     
    // Driver code
    public static void Main ()
    {
        int x1 = 1, x2 = 1, x3 = 1,
            y1 = 1, y2 = 4, y3 = 5;
                             
        collinear(x1, y1, x2, y2, x3, y3);
    }
}
 
// This code is contributed by Sam007.

Javascript

// Javascript program to check if three
// points are collinear or not
// using area of triangle.
 
function collinear(x1,  y1,  x2, y2,  x3,  y3)
{
 
    // Calculation the area of
    // triangle. We have skipped
    // multiplication with 0.5
    // to avoid floating point
    // computations
    var a = x1 * (y2 - y3) +
            x2 * (y3 - y1) +
            x3 * (y1 - y2);
 
    if (a == 0)
        document.write("Yes");
    else
        document.write( "No");
}
 
var x1 = 1, x2 = 1, x3 = 1,y1 = 1, y2 = 4, y3 = 5;
    collinear(x1, y1, x2, y2, x3, y3);
 
// This code is contributed by akshitsaxenaa09.

输出 ：

Yes

第二种方法

For three points, slope of any pair of points
must be same as other pair.

For example, slope of line joining (x2, y2)
and (x3, y3), and line joining (x1, y1) and
(x2, y2) must be same.

(y3 - y2)/(x3 - x2) = (y2 - y1)/(x2 - x1)

In other words, 
(y3 - y2)(x2 - x1) = (y2 - y1)(x3 - x2) 

如果这等于零，则点位于一条直线上

C

// Slope based solution to check
// if three points are collinear.
#include 
#include 
 
/* function to check if
point collinear or not*/
void collinear(int x1, int y1, int x2,
               int y2, int x3, int y3)
{
    if ((y3 - y2) * (x2 - x1) ==
        (y2 - y1) * (x3 - x2))
        printf("Yes");
    else
        printf("No");
}
 
// Driver Code
int main()
{
    int x1 = 1, x2 = 1, x3 = 0,
        y1 = 1, y2 = 6, y3 = 9;
    collinear(x1, y1, x2, y2, x3, y3);
    return 0;
}

Java

// Slope based solution to check
// if three points are collinear.
 
import java.io.*;
 
class GFG {
 
/* function to check if
point collinear or not*/
static void cool_line(int x1, int y1, int x2,
            int y2, int x3, int y3)
{
    if ((y3 - y2) * (x2 - x1) ==
        (y2 - y1) * (x3 - x2))
        System.out.println("Yes");
    else
        System.out.println("No");
}
 
// Driver Code
     
    public static void main (String[] args) {
        int a1 = 1, a2 = 1, a3 = 0,
        b1 = 1, b2 = 6, b3 = 9;
       cool_line(a1, b1, a2, b2, a3, b3);
         
         
    }
}
//This Code is Contributed by ajit

Python

# Slope based solution to check if three
# points are collinear.
  
# function to check if
# point collinear or not
def collinear(x1, y1, x2, y2, x3, y3):
    
    if ((y3 - y2)*(x2 - x1) == (y2 - y1)*(x3 - x2)):
        print ("Yes")
    else:
        print ("No")
  
# Driver Code
x1, x2, x3, y1, y2, y3 = 1, 1, 0, 1, 6, 9
collinear(x1, y1, x2, y2, x3, y3);
 
# This code is contributed
# by Sachin Bisht

C＃

// Slope based solution to check
// if three points are collinear.
using System;
 
class GFG
{
     
/* function to check if
point collinear or not*/
static void cool_line(int x1, int y1, int x2,
                      int y2, int x3, int y3)
{
    if ((y3 - y2) * (x2 - x1) ==
        (y2 - y1) * (x3 - x2))
        Console.WriteLine("Yes");
    else
        Console.WriteLine("No");
}
 
// Driver Code
static public void Main ()
{
    int a1 = 1, a2 = 1, a3 = 0,
    b1 = 1, b2 = 6, b3 = 9;
    cool_line(a1, b1, a2, b2, a3, b3);
}
}
 
// This code is contributed by ajit

Javascript

// Slope based solution to check
// if three points are collinear.
/*
     * function to check if povar collinear or not
     */
    function cool_line(x1 , y1 , x2 , y2 , x3 , y3)
    {
        if ((y3 - y2) * (x2 - x1) == (y2 - y1) * (x3 - x2))
            document.write("Yes");
        else
            document.write("No");
    }
 
    // Driver Code
        var a1 = 1, a2 = 1, a3 = 0, b1 = 1, b2 = 6, b3 = 9;
        cool_line(a1, b1, a2, b2, a3, b3);
 
// This code is contributed by aashish1995

输出 ：

No 

如果您希望与专家一起参加现场课程，请参阅DSA 现场工作专业课程和学生竞争性编程现场课程。