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📜  可以内接在正圆锥内的最大立方体

📅  最后修改于: 2021-10-23 09:04:32             🧑  作者: Mango

给定一个半径为r且垂直高度为h的正圆锥。我们必须找到可以内接的最大立方体的边长。
例子

Input : h = 5, r = 6
Output : 3.14613

Input : h = 8, r = 12
Output : 5.43698

方法
让,立方体的边 = a
从图中我们可以清楚地理解使用三角形的性质: BC/AB = DE/AD。
所以,

r/h = (a/√2)/(h-a)

or, a = h*r√2/(h+√2*r)

下面是上述方法的实现:

C++
// C++ Program to find the biggest cube
// inscribed within a right circular cone
#include 
using namespace std;
 
// Function to find the side of the cube
float cubeSide(float h, float r)
{
    // height and radius cannot be negative
    if (h < 0 && r < 0)
        return -1;
 
    // side of the cube
    float a = (h * r * sqrt(2)) / (h + sqrt(2) * r);
 
    return a;
}
 
// Driver code
int main()
{
    float h = 5, r = 6;
 
    cout << cubeSide(h, r) << endl;
 
    return 0;
}


Java
// Java Program to find the the biggest cube
// which can be inscribed within a right circular cone
 
import java.io.*;
 
class GFG {
 
 
// Function to find the side of the cube
 
static float cube(float h, float r)
{
 
    // hegiht and radius cannot be negative
    if (h < 0 && r < 0)
        return -1;
 
 // side of the cube
    float a = (h * r * (float)Math.sqrt(2)) / (h + (float)Math.sqrt(2) * r);
   
    return a;
}
 
// Driver code
   
    public static void main (String[] args) {
          float h = 5, r = 6;
    System.out.println( cube(h, r));
    }
}
 
// this article is contributed by Ishwar Gupta


Python 3
# Python3 Program to find the biggest cube
# inscribed within a right circular cone
import math
 
# Function to find the side of the cube
def cubeSide(h, r):
 
    # height and radius cannot
    # be negative
    if (h < 0 and r < 0):
        return -1
 
    # side of the cube
    a = ((h * r * math.sqrt(2)) /
         (h + math.sqrt(2) * r))
 
    return a
 
# Driver code
h = 5; r = 6;
 
print(cubeSide(h, r), "\n")
 
# This code is contributed
# by Akanksha Rai


C#
// C# Program to find the the
// biggest cube which can be
// inscribed within a right
// circular cone
using System;
 
class GFG
{
 
// Function to find the side
// of the cube
static float cube(float h, float r)
{
 
// hegiht and radius cannot be negative
if (h < 0 && r < 0)
    return -1;
 
// side of the cube
float a = (h * r * (float)Math.Sqrt(2)) /
          (h + (float)Math.Sqrt(2) * r);
 
    return a;
}
 
// Driver code
public static void Main ()
{
    float h = 5, r = 6;
    Console.Write( cube(h, r));
}
}
 
// This code is contributed
// by 29AjayKumar


PHP


Javascript


输出:
3.14613

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