📜  从已排序的双向链表中删除重复项

📅  最后修改于: 2022-05-13 01:57:44.762000             🧑  作者: Mango

从已排序的双向链表中删除重复项

给定一个包含n 个节点的已排序双向链表。问题是从给定的列表中删除重复的节点。

例子:

算法:

removeDuplicates(head_ref, x)
      if head_ref == NULL
          return
      Initialize current = head_ref
      while current->next != NULL
           if current->data == current->next->data
               deleteNode(head_ref, current->next)
           else
               current = current->next

这篇文章讨论了deleteNode(head_ref, current)的算法使用指向节点的指针删除节点)。



C++
/* C++ implementation to remove duplicates from a
   sorted doubly linked list */
#include 
 
using namespace std;
 
/* a node of the doubly linked list */
struct Node {
    int data;
    struct Node* next;
    struct Node* prev;
};
 
/* Function to delete a node in a Doubly Linked List.
   head_ref --> pointer to head node pointer.
   del  -->  pointer to node to be deleted. */
void deleteNode(struct Node** head_ref, struct Node* del)
{
    /* base case */
    if (*head_ref == NULL || del == NULL)
        return;
 
    /* If node to be deleted is head node */
    if (*head_ref == del)
        *head_ref = del->next;
 
    /* Change next only if node to be deleted
        is NOT the last node */
    if (del->next != NULL)
        del->next->prev = del->prev;
 
    /* Change prev only if node to be deleted
       is NOT the first node */
    if (del->prev != NULL)
        del->prev->next = del->next;
 
    /* Finally, free the memory occupied by del*/
    free(del);
}
 
/* function to remove duplicates from a
   sorted doubly linked list */
void removeDuplicates(struct Node** head_ref)
{
    /* if list is empty */
    if ((*head_ref) == NULL)
        return;
 
    struct Node* current = *head_ref;
    struct Node* next;
 
    /* traverse the list till the last node */
    while (current->next != NULL) {
 
        /* Compare current node with next node */
        if (current->data == current->next->data)
 
            /* delete the node pointed to by
              'current->next' */
            deleteNode(head_ref, current->next);
 
        /* else simply move to the next node */
        else
            current = current->next;
    }
}
 
/* Function to insert a node at the beginning
   of the Doubly Linked List */
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node =
           (struct Node*)malloc(sizeof(struct Node));
 
    /* put in the data  */
    new_node->data = new_data;
 
    /* since we are adding at the beginning,
    prev is always NULL */
    new_node->prev = NULL;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);
 
    /* change prev of head node to new node */
    if ((*head_ref) != NULL)
        (*head_ref)->prev = new_node;
 
    /* move the head to point to the new node */
    (*head_ref) = new_node;
}
 
/* Function to print nodes in a given doubly linked list */
void printList(struct Node* head)
{
    /* if list is empty */
    if (head == NULL)
        cout << "Doubly Linked list empty";
 
    while (head != NULL) {
        cout << head->data << " ";
        head = head->next;
    }
}
 
/* Driver program to test above functions*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
 
    /* Create the doubly linked list:
     4<->4<->4<->4<->6<->8<->8<->10<->12<->12 */
    push(&head, 12);
    push(&head, 12);
    push(&head, 10);
    push(&head, 8);
    push(&head, 8);
    push(&head, 6);
    push(&head, 4);
    push(&head, 4);
    push(&head, 4);
    push(&head, 4);
 
    cout << "Original Doubly linked list:n";
    printList(head);
 
    /* remove duplicate nodes */
    removeDuplicates(&head);
 
    cout << "\nDoubly linked list after"
             " removing duplicates:n";
    printList(head);
 
    return 0;
}


Java
/* Java implementation to remove duplicates from a 
   sorted doubly linked list */
public class removeDuplicatesFromSortedList {
 
    /* function to remove duplicates from a 
   sorted doubly linked list */
    public static void removeDuplicates(Node head)
    {
        /* if list is empty */
        if (head== null)
            return;
   
        Node current = head;
 
        /* traverse the list till the last node */
        while (current.next != null)
        {
            /* Compare current node with next node */
            if (current.data == current.next.data)
                /* delete the node pointed to by
              ' current->next' */
                deleteNode(head, current.next);
   
            /* else simply move to the next node */
            else
                current = current.next;
        } 
          
    }
 
 
    /* Function to delete a node in a Doubly Linked List.
    head_ref --> pointer to head node pointer.
    del  -->  pointer to node to be deleted. */
    public static void deleteNode(Node head, Node del)
    {
         /* base case */
        if(head==null || del==null)
        {
            return ;
        }
        /* If node to be deleted is head node */
        if(head==del)
        {
            head=del.next;
        }
        /* Change next only if node to be deleted 
        is NOT the last node */
        if(del.next!=null)
        {
            del.next.prev=del.prev;
        }
        /* Change prev only if node to be deleted 
       is NOT the first node */
        if (del.prev != null)
            del.prev.next = del.next;
 
    }
 
 
    /* Function to insert a node at the beginning 
    of the Doubly Linked List */
    public static Node push(Node head, int data)
    {
        /* allocate node */
        Node newNode=new Node(data);
        /* since we are adding at the beginning,
        prev is always NULL */
        newNode.prev=null;
        /* link the old list off the new node */
        newNode.next =head;
        /* change prev of head node to new node */
        if(head!=null)
        {
            head.prev=newNode;
        }
        head=newNode;
        return head;
    }
 
    /* Function to print nodes in a given doubly linked list */
    public static void printList(Node head)
    {
        if (head == null)
            System.out.println("Doubly Linked list empty");
         
        while (head != null)
        {
            System.out.print(head.data+" ") ;
            head = head.next;
        }
    }
 
    public static void main(String args[]) {
        Node head=null;
        head=push(head, 12);
        head=push(head, 12);
        head=push(head, 10);
        head=push(head, 8);
        head=push(head, 8);
        head=push(head, 6);
        head=push(head, 4);
        head=push(head, 4);
        head=push(head, 4);
        head=push(head, 4);
 
        System.out.println("Original Doubly LinkedList");
        printList(head);
 
        /* remove duplicate nodes */
        removeDuplicates(head);
        System.out.println("\nDoubly linked list after removing duplicates:");
        printList(head);
    }
}
class Node
{
    int data;
    Node next,prev;
 
    Node(int data)
    {
        this.data=data;
        next=null;
        prev=null;
    }
}
//This code is contributed by Gaurav Tiwari


Python
# Python implementation to remove duplicates from a
# sorted doubly linked list
 
# A linked list node
class Node:
    def __init__(self, new_data):
        self.data = new_data
        self.next = None
        self.prev = None
 
# Function to _delete a node in a Doubly Linked List.
# head_ref -. pointer to head node pointer.
# _del -. pointer to node to be _deleted.
def _deleteNode(head_ref, _del):
 
    # base case
    if (head_ref == None or _del == None):
        return
 
    # If node to be _deleted is head node
    if (head_ref == _del):
        head_ref = _del.next
 
    # Change next only if node to be _deleted
    # is NOT the last node
    if (_del.next != None):
        _del.next.prev = _del.prev
 
    # Change prev only if node to be _deleted
    # is NOT the first node
    if (_del.prev != None):
        _del.prev.next = _del.next
 
    return head_ref
 
# function to remove duplicates from a
# sorted doubly linked list
def removeDuplicates(head_ref):
 
    # if list is empty
    if ((head_ref) == None):
        return None
 
    current = head_ref
    next = None
 
    # traverse the list till the last node
    while (current.next != None) :
 
        # Compare current node with next node
        if (current.data == current.next.data):
 
            # _delete the node pointed to by
            # 'current.next'
            _deleteNode(head_ref, current.next)
 
        # else simply move to the next node
        else:
            current = current.next
     
    return head_ref
     
# Function to insert a node at the beginning
# of the Doubly Linked List
def push(head_ref, new_data):
 
    # allocate node
    new_node = Node(0)
 
    # put in the data
    new_node.data = new_data
 
    # since we are adding at the beginning,
    # prev is always None
    new_node.prev = None
 
    # link the old list off the new node
    new_node.next = (head_ref)
 
    # change prev of head node to new node
    if ((head_ref) != None):
        (head_ref).prev = new_node
 
    # move the head to point to the new node
    (head_ref) = new_node
     
    return head_ref
 
# Function to print nodes in a given doubly linked list
def printList(head):
 
    # if list is empty
    if (head == None):
        print("Doubly Linked list empty")
 
    while (head != None) :
        print(head.data, end = " ")
        head = head.next
     
# Driver program to test above functions
 
# Start with the empty list
head = None
 
# Create the doubly linked list:
# 4<->4<->4<->4<->6<->8<->8<->10<->12<->12
head = push(head, 12)
head = push(head, 12)
head = push(head, 10)
head = push(head, 8)
head = push(head, 8)
head = push(head, 6)
head = push(head, 4)
head = push(head, 4)
head = push(head, 4)
head = push(head, 4)
 
print( "Original Doubly linked list:\n")
printList(head)
 
# remove duplicate nodes
head = removeDuplicates(head)
 
print("\nDoubly linked list after removing duplicates:")
printList(head)
 
# This code is contributed by Arnab Kundu


C#
/* C# implementation to remove duplicates from a
sorted doubly linked list */
using System;
 
public class removeDuplicatesFromSortedList
{
 
    /* function to remove duplicates from a
    sorted doubly linked list */
    public static void removeDuplicates(Node head)
    {
        /* if list is empty */
        if (head == null)
            return;
     
        Node current = head; 
     
        /* traverse the list till the last node */
        while (current.next != null)
        {
     
            /* Compare current node with next node */
            if (current.data == current.next.data)
             
            /* delete the node pointed to by
            'current->next' */
                deleteNode(head, current.next);
     
            /* else simply move to the next node */
            else
                current = current.next;
        }
    }
 
 
    /* Function to delete a node in a Doubly Linked List.
    head_ref --> pointer to head node pointer.
    del --> pointer to node to be deleted. */
    public static void deleteNode(Node head, Node del)
    {
        /* base case */
        if(head == null || del == null)
        {
            return ;
        }
         
        /* If node to be deleted is head node */
        if(head == del)
        {
            head = del.next;
        }
         
        /* Change next only if node to be deleted
        is NOT the last node */
        if(del.next != null)
        {
            del.next.prev = del.prev;
        }
         
        /* Change prev only if node to be deleted
        is NOT the first node */
        if (del.prev != null)
            del.prev.next = del.next;
 
    }
 
 
    /* Function to insert a node at the beginning
    of the Doubly Linked List */
    public static Node push(Node head, int data)
    {
        /* allocate node */
        Node newNode = new Node(data);
         
        /* since we are adding at the beginning,
        prev is always NULL */
        newNode.prev = null;
         
        /* link the old list off the new node */
        newNode.next = head;
         
        /* change prev of head node to new node */
        if(head != null)
        {
            head.prev = newNode;
        }
        head = newNode;
        return head;
    }
 
    /* Function to print nodes in a given doubly linked list */
    public static void printList(Node head)
    {
        if (head == null)
            Console.WriteLine("Doubly Linked list empty");
         
        while (head != null)
        {
            Console.Write(head.data + " ") ;
            head = head.next;
        }
    }
 
    // Driver code
    public static void Main(String []args)
    {
        Node head = null;
        head = push(head, 12);
        head = push(head, 12);
        head = push(head, 10);
        head = push(head, 8);
        head = push(head, 8);
        head = push(head, 6);
        head = push(head, 4);
        head = push(head, 4);
        head = push(head, 4);
        head = push(head, 4);
 
        Console.WriteLine("Original Doubly LinkedList");
        printList(head);
 
        /* remove duplicate nodes */
        removeDuplicates(head);
        Console.WriteLine("\nDoubly linked list after" +
                            "removing duplicates:");
        printList(head);
    }
}
 
public class Node
{
    public int data;
    public Node next,prev;
 
    public Node(int data)
    {
        this.data = data;
        next = null;
        prev = null;
    }
}
 
// This code is contributed by 29AjayKumar.


Javascript


输出:

Original Doubly linked list:
4 4 4 4 6 8 8 10 12 12
Doubly linked list after removing duplicates:
4 6 8 10 12

时间复杂度: O(n)

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