双向链表合并排序的C程序
给定一个双向链表,编写一个函数,使用归并排序对双向链表进行升序排序。
比如下面的双向链表要改成24810
已经讨论了单链表的合并排序。这里的重要变化是在合并两个列表时也修改了先前的指针。
下面是双向链表合并排序的实现。
C
// C program for merge sort on doubly
// linked list
#include
#include
struct Node
{
int data;
struct Node *next, *prev;
};
struct Node *split(struct Node *head);
// Function to merge two linked lists
struct Node *merge(struct Node *first,
struct Node *second)
{
// If first linked list is empty
if (!first)
return second;
// If second linked list is empty
if (!second)
return first;
// Pick the smaller value
if (first->data < second->data)
{
first->next = merge(first->next,second);
first->next->prev = first;
first->prev = NULL;
return first;
}
else
{
second->next = merge(first,second->next);
second->next->prev = second;
second->prev = NULL;
return second;
}
}
// Function to do merge sort
struct Node *mergeSort(struct Node *head)
{
if (!head || !head->next)
return head;
struct Node *second = split(head);
// Recur for left and right halves
head = mergeSort(head);
second = mergeSort(second);
// Merge the two sorted halves
return merge(head,second);
}
// A utility function to insert a new node
// at the beginning of doubly linked list
void insert(struct Node **head, int data)
{
struct Node *temp =
(struct Node *)malloc(sizeof(struct Node));
temp->data = data;
temp->next = temp->prev = NULL;
if (!(*head))
(*head) = temp;
else
{
temp->next = *head;
(*head)->prev = temp;
(*head) = temp;
}
}
// A utility function to print a doubly
// linked list in both forward and backward
// directions
void print(struct Node *head)
{
struct Node *temp = head;
printf(
"Forward Traversal using next pointer");
while (head)
{
printf("%d ",head->data);
temp = head;
head = head->next;
}
printf(
"Backward Traversal using prev pointer");
while (temp)
{
printf("%d ", temp->data);
temp = temp->prev;
}
}
// Utility function to swap two integers
void swap(int *A, int *B)
{
int temp = *A;
*A = *B;
*B = temp;
}
// Split a doubly linked list (DLL) into
// 2 DLLs of half sizes
struct Node *split(struct Node *head)
{
struct Node *fast = head,*slow = head;
while (fast->next && fast->next->next)
{
fast = fast->next->next;
slow = slow->next;
}
struct Node *temp = slow->next;
slow->next = NULL;
return temp;
}
// Driver program
int main(void)
{
struct Node *head = NULL;
insert(&head,5);
insert(&head,20);
insert(&head,4);
insert(&head,3);
insert(&head,30);
insert(&head,10);
head = mergeSort(head);
printf(
"Linked List after sorting");
print(head);
return 0;
}
输出:
Linked List after sorting
Forward Traversal using next pointer
3 4 5 10 20 30
Backward Traversal using prev pointer
30 20 10 5 4 3
时间复杂度:上述实现的时间复杂度与数组的 MergeSort 的时间复杂度相同。它需要 Θ(nLogn) 时间。
空间复杂度: O(1)。我们只使用恒定数量的额外空间。
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