循环链表的节点总和

给定一个单循环链表。任务是找到给定链表的节点总和。

对于上述循环列表，sum = 2 + 5 + 7 + 8 + 10 = 32
例子：

Input: 11->2->56->12
Output: Sum of Circular linked list is = 81

Input: 2-> 5 -> 7 -> 8 -> 10
Output: Sum of Circular linked list is = 32   

方法：

1. 用链表的头部初始化一个指针 temp，用 0 初始化一个 sum 变量。
2. 使用循环开始遍历链表，直到遍历完所有节点。
   • 将当前节点的值添加到总和中，即 sum += temp -> data。
   • 增加指向链表下一个节点的指针，即 temp = temp -> next。
3. 返回总和。

下面是上述方法的实现：

C++

// CPP program to find the sum of all nodes
// of a Circular linked list
 
#include 
using namespace std;
 
// Structure for a node
struct Node {
    int data;
    struct Node* next;
};
 
// Function to insert a node at the beginning
// of a Circular linked list
void push(struct Node** head_ref, int data)
{
    struct Node* ptr1 = (struct Node*)malloc(sizeof(struct Node));
    struct Node* temp = *head_ref;
    ptr1->data = data;
    ptr1->next = *head_ref;
 
    // If linked list is not NULL then
    // set the next of last node
    if (*head_ref != NULL) {
        while (temp->next != *head_ref)
            temp = temp->next;
        temp->next = ptr1;
    }
    else
        ptr1->next = ptr1; // For the first node
 
    *head_ref = ptr1;
}
 
// Function to find sum of the given
// Circular linked list
int sumOfList(struct Node* head)
{
    struct Node* temp = head;
    int sum = 0;
    if (head != NULL) {
        do {
            temp = temp->next;
            sum += temp->data;
        } while (temp != head);
    }
 
    return sum;
}
 
// Driver code
int main()
{
    // Initialize lists as empty
    struct Node* head = NULL;
 
    // Created linked list will be 11->2->56->12
    push(&head, 12);
    push(&head, 56);
    push(&head, 2);
    push(&head, 11);
 
    cout << "Sum of Circular linked list is = " << sumOfList(head);
 
    return 0;
}

Java

// Java program to find the sum of
// all nodes of a Circular linked list
import java.util.*;
 
class GFG
{
 
// structure for a node
static class Node
{
    int data;
    Node next;
};
 
// Function to insert a node
// at the beginning of a
// Circular linked list
static Node push(Node head_ref,
                      int data)
{
    Node ptr1 = new Node();
    Node temp = head_ref;
    ptr1.data = data;
    ptr1.next = head_ref;
 
    // If linked list is not null then
    // set the next of last node
    if (head_ref != null)
    {
        while (temp.next != head_ref)
            temp = temp.next;
        temp.next = ptr1;
    }
    else
        ptr1.next = ptr1; // For the first node
 
    head_ref = ptr1;
     
    return head_ref;
}
 
// Function to find sum of the
// given Circular linked list
static int sumOfList(Node head)
{
    Node temp = head;
    int sum = 0;
    if (head != null)
    {
        do
        {
            temp = temp.next;
            sum += temp.data;
        } while (temp != head);
    }
 
    return sum;
}
 
// Driver code
public static void main(String args[])
{
    // Initialize lists as empty
    Node head = null;
 
    // Created linked list will
    // be 11.2.56.12
    head = push(head, 12);
    head = push(head, 56);
    head = push(head, 2);
    head = push(head, 11);
 
    System.out.println("Sum of Circular linked" +
                " list is = " + sumOfList(head));
}
}
 
// This code is contributed by Arnab Kundu

Python3

# Python3 program to find the sum of all nodes
# of a Circular linked list
import math
 
# class for a node
class Node:
    def __init__(self,data):
        self.data = data
        self.next = None
 
# Function to insert a node at the beginning
# of a Circular linked list
def push(head, data):
    if not head:
        head = Node(data)
        head.next = head
        return head
    lnode = head
 
    # If linked list is not NULL then
    # set the next of last node
    while(lnode and lnode.next is not head):
        lnode = lnode.next
    ptr1 = Node(data) # For the first node
    ptr1.next = head
    lnode.next = ptr1
    head = ptr1
    return head
 
# Function to find sum of the given
# Circular linked list    
def sumOfList(head):
    temp = head
    tsum = temp.data
    temp = temp.next
    while(temp is not head):
        tsum += temp.data
        temp = temp.next
    return tsum
 
# Driver code
if __name__=='__main__':
     
    # Initialize lists as empty
    head = None
 
    # Created linked list will be 11->2->56->12
    head = push(head, 12)
    head = push(head, 56)
    head = push(head, 2)
    head = push(head, 11)
    print("Sum of circular list is = {}" .
                  format(sumOfList(head)))
 
# This code is contributed by Vikash Kumar 37

C#

// C# program to find the sum of
// all nodes of a Circular linked list
using System;
 
class GFG
{
 
    // structure for a node
    class Node
    {
        public int data;
        public Node next;
    };
 
    // Function to insert a node
    // at the beginning of a
    // Circular linked list
    static Node push(Node head_ref,
                        int data)
    {
        Node ptr1 = new Node();
        Node temp = head_ref;
        ptr1.data = data;
        ptr1.next = head_ref;
 
        // If linked list is not null then
        // set the next of last node
        if (head_ref != null)
        {
            while (temp.next != head_ref)
                temp = temp.next;
            temp.next = ptr1;
        }
        else
            ptr1.next = ptr1; // For the first node
 
        head_ref = ptr1;
 
        return head_ref;
    }
 
    // Function to find sum of the
    // given Circular linked list
    static int sumOfList(Node head)
    {
        Node temp = head;
        int sum = 0;
        if (head != null)
        {
            do
            {
                temp = temp.next;
                sum += temp.data;
            } while (temp != head);
        }
 
        return sum;
    }
 
    // Driver code
    public static void Main()
    {
        // Initialize lists as empty
        Node head = null;
 
        // Created linked list will
        // be 11.2.56.12
        head = push(head, 12);
        head = push(head, 56);
        head = push(head, 2);
        head = push(head, 11);
 
        Console.WriteLine("Sum of Circular linked" +
                    " list is = " + sumOfList(head));
    }
}
 
// This code is contributed by princiraj1992

Javascript

 
// JavaScript program to find the sum of
// all nodes of a Circular linked list
 
    // structure for a node
 
class Node {
        constructor() {
            this.data = 0;
            this.next = null;
        }
    }
 
 
    // Function to insert a node
    // at the beginning of a
    // Circular linked list
    function push(head_ref , data) {
    var ptr1 = new Node();
    var temp = head_ref;
        ptr1.data = data;
        ptr1.next = head_ref;
 
        // If linked list is not null then
        // set the next of last node
        if (head_ref != null) {
            while (temp.next != head_ref)
                temp = temp.next;
            temp.next = ptr1;
        } else
            ptr1.next = ptr1; // For the first node
 
        head_ref = ptr1;
 
        return head_ref;
    }
 
    // Function to find sum of the
    // given Circular linked list
    function sumOfList(head) {
    var temp = head;
        var sum = 0;
        if (head != null) {
            do {
                temp = temp.next;
                sum += temp.data;
            } while (temp != head);
        }
 
        return sum;
    }
 
    // Driver code
     
        // Initialize lists as empty
       var head = null;
 
        // Created linked list will
        // be 11.2.56.12
        head = push(head, 12);
        head = push(head, 56);
        head = push(head, 2);
        head = push(head, 11);
 
        document.write("Sum of Circular linked"
        + " list is = " + sumOfList(head));
 
// This code contributed by aashish1995
 

输出：

Sum of Circular linked list is = 81

时间复杂度：O(N)，其中 N 是链表中的节点数。
辅助空间： O(1)