📅  最后修改于: 2020-11-06 05:43:55             🧑  作者: Mango
在本章中,我们将讨论如何对日期进行切片和切块,并通常获得熊猫对象的子集。
Python和NumPy索引运算符“ []”和属性运算符“”。可以在各种用例中快速轻松地访问Pandas数据结构。但是,由于事先不知道要访问的数据类型,因此直接使用标准运算符存在一些优化限制。对于生产代码,我们建议您利用本章中介绍的优化的熊猫数据访问方法。
熊猫现在支持三种类型的多轴索引:下表中提到了三种类型-
Sr.No | Indexing & Description |
---|---|
1 |
.loc() Label based |
2 |
.iloc() Integer based |
3 |
.ix() Both Label and Integer based |
熊猫提供了多种方法来具有纯粹基于标签的索引。切片时,还包括起始边界。整数是有效的标签,但它们引用标签而不是位置。
.loc()具有多种访问方法,例如-
loc需要两个单/列表/范围运算符,以“,”分隔。第一个指示行,第二个指示列。
#import the pandas library and aliasing as pd
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4),
index = ['a','b','c','d','e','f','g','h'], columns = ['A', 'B', 'C', 'D'])
#select all rows for a specific column
print df.loc[:,'A']
其输出如下-
a 0.391548
b -0.070649
c -0.317212
d -2.162406
e 2.202797
f 0.613709
g 1.050559
h 1.122680
Name: A, dtype: float64
# import the pandas library and aliasing as pd
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4),
index = ['a','b','c','d','e','f','g','h'], columns = ['A', 'B', 'C', 'D'])
# Select all rows for multiple columns, say list[]
print df.loc[:,['A','C']]
其输出如下-
A C
a 0.391548 0.745623
b -0.070649 1.620406
c -0.317212 1.448365
d -2.162406 -0.873557
e 2.202797 0.528067
f 0.613709 0.286414
g 1.050559 0.216526
h 1.122680 -1.621420
# import the pandas library and aliasing as pd
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4),
index = ['a','b','c','d','e','f','g','h'], columns = ['A', 'B', 'C', 'D'])
# Select few rows for multiple columns, say list[]
print df.loc[['a','b','f','h'],['A','C']]
其输出如下-
A C
a 0.391548 0.745623
b -0.070649 1.620406
f 0.613709 0.286414
h 1.122680 -1.621420
# import the pandas library and aliasing as pd
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4),
index = ['a','b','c','d','e','f','g','h'], columns = ['A', 'B', 'C', 'D'])
# Select range of rows for all columns
print df.loc['a':'h']
其输出如下-
A B C D
a 0.391548 -0.224297 0.745623 0.054301
b -0.070649 -0.880130 1.620406 1.419743
c -0.317212 -1.929698 1.448365 0.616899
d -2.162406 0.614256 -0.873557 1.093958
e 2.202797 -2.315915 0.528067 0.612482
f 0.613709 -0.157674 0.286414 -0.500517
g 1.050559 -2.272099 0.216526 0.928449
h 1.122680 0.324368 -1.621420 -0.741470
# import the pandas library and aliasing as pd
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4),
index = ['a','b','c','d','e','f','g','h'], columns = ['A', 'B', 'C', 'D'])
# for getting values with a boolean array
print df.loc['a']>0
其输出如下-
A False
B True
C False
D False
Name: a, dtype: bool
熊猫提供了多种方法来获得纯粹基于整数的索引。像Python和numpy一样,它们都是基于0的索引。
各种访问方法如下-
# import the pandas library and aliasing as pd
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
# select all rows for a specific column
print df.iloc[:4]
其输出如下-
A B C D
0 0.699435 0.256239 -1.270702 -0.645195
1 -0.685354 0.890791 -0.813012 0.631615
2 -0.783192 -0.531378 0.025070 0.230806
3 0.539042 -1.284314 0.826977 -0.026251
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
# Integer slicing
print df.iloc[:4]
print df.iloc[1:5, 2:4]
其输出如下-
A B C D
0 0.699435 0.256239 -1.270702 -0.645195
1 -0.685354 0.890791 -0.813012 0.631615
2 -0.783192 -0.531378 0.025070 0.230806
3 0.539042 -1.284314 0.826977 -0.026251
C D
1 -0.813012 0.631615
2 0.025070 0.230806
3 0.826977 -0.026251
4 1.423332 1.130568
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
# Slicing through list of values
print df.iloc[[1, 3, 5], [1, 3]]
print df.iloc[1:3, :]
print df.iloc[:,1:3]
其输出如下-
B D
1 0.890791 0.631615
3 -1.284314 -0.026251
5 -0.512888 -0.518930
A B C D
1 -0.685354 0.890791 -0.813012 0.631615
2 -0.783192 -0.531378 0.025070 0.230806
B C
0 0.256239 -1.270702
1 0.890791 -0.813012
2 -0.531378 0.025070
3 -1.284314 0.826977
4 -0.460729 1.423332
5 -0.512888 0.581409
6 -1.204853 0.098060
7 -0.947857 0.641358
除了基于纯标签和基于整数的方法外,Pandas还提供了一种混合方法,用于使用.ix()运算符进行选择和子集化。
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
# Integer slicing
print df.ix[:4]
其输出如下-
A B C D
0 0.699435 0.256239 -1.270702 -0.645195
1 -0.685354 0.890791 -0.813012 0.631615
2 -0.783192 -0.531378 0.025070 0.230806
3 0.539042 -1.284314 0.826977 -0.026251
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
# Index slicing
print df.ix[:,'A']
其输出如下-
0 0.699435
1 -0.685354
2 -0.783192
3 0.539042
4 -1.044209
5 -1.415411
6 1.062095
7 0.994204
Name: A, dtype: float64
通过多轴索引从Pandas对象获取值使用以下符号-
Object | Indexers | Return Type |
---|---|---|
Series | s.loc[indexer] | Scalar value |
DataFrame | df.loc[row_index,col_index] | Series object |
Panel | p.loc[item_index,major_index, minor_index] |
p.loc[item_index,major_index, minor_index] |
注意-.iloc()和.ix()应用相同的索引选项和返回值。
现在让我们看看如何对DataFrame对象执行每个操作。我们将使用基本索引运算符'[]’-
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
print df['A']
其输出如下-
0 -0.478893
1 0.391931
2 0.336825
3 -1.055102
4 -0.165218
5 -0.328641
6 0.567721
7 -0.759399
Name: A, dtype: float64
注意-我们可以将值列表传递给[]以选择那些列。
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
print df[['A','B']]
其输出如下-
A B
0 -0.478893 -0.606311
1 0.391931 -0.949025
2 0.336825 0.093717
3 -1.055102 -0.012944
4 -0.165218 1.550310
5 -0.328641 -0.226363
6 0.567721 -0.312585
7 -0.759399 -0.372696
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
print df[2:2]
其输出如下-
Columns: [A, B, C, D]
Index: []
可以使用属性运算符“。”选择列。
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randn(8, 4), columns = ['A', 'B', 'C', 'D'])
print df.A
其输出如下-
0 -0.478893
1 0.391931
2 0.336825
3 -1.055102
4 -0.165218
5 -0.328641
6 0.567721
7 -0.759399
Name: A, dtype: float64