具有更新查询的二进制数组中的第k个设置位的索引

给定以下类型的二进制数组arr []和q查询：

1. k：在数组中找到第k^个设置位的索引，即k ^th 1 。
2. (x，y)：更新arr [x] = y ，其中y可以为0或1 。

例子：

Input: arr[] = {1, 0, 1, 0, 0, 1, 1, 1}, q = 2
k = 4
(x, y) = (5, 1)
Output:
Index of 4th set bit: 6
Array after updation:
1 0 1 0 0 0 1 1

方法：一个简单的解决方案是运行一个从0到n – 1的循环并找到第k^个1 。要更新值，只需执行arr [i] = x即可。第一次操作花费O(n)时间，第二次操作花费O(1)时间。

另一个解决方案是创建另一个数组，并将每个1的索引存储在此数组的^第i^个索引处。现在可以在O(1)时间中计算K ^th 1的索引，但是现在更新操作需要O(n)时间。如果查询操作的数量很大且更新很少，则此方法效果很好。

但是，如果查询和更新的数量相等怎么办?我们可以使用段树在O(log n)时间内执行这两项操作，并在O(Logn)时间内进行两项操作。

Representation of Segment tree:

1. Leaf Nodes are the elements of the input array.
2. Each internal node represents sum merging of the leaf nodes.

An array representation of tree is used to represent Segment Trees. For each node at index i, the left child is at index 2*i+1, right child at 2*i+2 and the parent is at (i-1)/2.

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
  
// Function to build the tree
void buildTree(int* tree, int* a, int s, int e, int idx)
{
    // s = starting index
    // e = ending index
    // a = array storing binary string of numbers
    // idx = starting index = 1, for recurring the tree
    if (s == e) {
  
        // store each element value at the
        // leaf node
        tree[idx] = a[s];
        return;
    }
  
    int mid = (s + e) / 2;
  
    // Recurring in two sub portions (left, right)
    // to build the segment tree
  
    // Calling for the left sub portion
    buildTree(tree, a, s, mid, 2 * idx);
  
    // Calling for the right sub portion
    buildTree(tree, a, mid + 1, e, 2 * idx + 1);
  
    // Summing up the number of one's
    tree[idx] = tree[2 * idx] + tree[2 * idx + 1];
  
    return;
}
  
// Function to return the index of the query
int queryTree(int* tree, int s, int e, int k, int idx)
{
    // s = starting index
    // e = ending index
    // k = searching for kth bit
    // idx = starting index = 1, for recurring the tree
  
    // k > number of 1's in a binary string
    if (k > tree[idx])
        return -1;
  
    // leaf node at which kth 1 is stored
    if (s == e)
        return s;
    int mid = (s + e) / 2;
  
    // If left sub-tree contains more or equal 1's
    // than required kth 1
    if (tree[2 * idx] >= k)
        return queryTree(tree, s, mid, k, 2 * idx);
  
    // If left sub-tree contains less 1's than
    // required kth 1 then recur in the right sub-tree
    else
        return queryTree(tree, mid + 1, e, k - tree[2 * idx], 2 * idx + 1);
}
  
// Function to perform the update query
void updateTree(int* tree, int s, int e, int i, int change, int idx)
{
    // s = starting index
    // e = ending index
    // i = index at which change is to be done
    // change = new changed bit
    // idx = starting index = 1, for recurring the tree
  
    // Out of bounds request
    if (i < s || i > e) {
        cout << "error";
        return;
    }
  
    // Leaf node of the required index i
    if (s == e) {
  
        // Replacing the node value with
        // the new changed value
        tree[idx] = change;
        return;
    }
  
    int mid = (s + e) / 2;
  
    // If the index i lies in the left sub-tree
    if (i >= s && i <= mid)
        updateTree(tree, s, mid, i, change, 2 * idx);
  
    // If the index i lies in the right sub-tree
    else
        updateTree(tree, mid + 1, e, i, change, 2 * idx + 1);
  
    // Merging both left and right sub-trees
    tree[idx] = tree[2 * idx] + tree[2 * idx + 1];
    return;
}
  
// Function to perform queries
void queries(int* tree, int* a, int q, int p, int k, int change, int n)
{
    int s = 0, e = n - 1, idx = 1;
    if (q == 1) {
        // q = 1 update, p = index at which change
        // is to be done, change = new bit
        a[p] = change;
        updateTree(tree, s, e, p, change, idx);
        cout << "Array after updation:\n";
        for (int i = 0; i < n; i++)
            cout << a[i] << " ";
        cout << "\n";
    }
    else {
        // q = 0, print kth bit
        cout << "Index of " << k << "th set bit: "
             << queryTree(tree, s, e, k, idx) << "\n";
    }
}
  
// Driver code
int main()
{
    int a[] = { 1, 0, 1, 0, 0, 1, 1, 1 };
    int n = sizeof(a) / sizeof(int);
  
    // Declaring & initializing the tree with
    // maximum possible size of the segment tree
    // and each value initially as 0
    int* tree = new int[4 * n + 1];
    for (int i = 0; i < 4 * n + 1; ++i) {
        tree[i] = 0;
    }
  
    // s and e are the starting and ending
    // indices respectively
    int s = 0, e = n - 1, idx = 1;
  
    // Build the segment tree
    buildTree(tree, a, s, e, idx);
  
    // Find index of kth set bit
    int q = 0, p = 0, change = 0, k = 4;
    queries(tree, a, q, p, k, change, n);
  
    // Update query
    q = 1, p = 5, change = 0;
    queries(tree, a, q, p, k, change, n);
  
    return 0;
}

Java

// Java implementation of the approach
import java.io.*;
import java.util.*;
  
class GFG 
{
  
    // Function to build the tree
    static void buildTree(int[] tree, int[] a, 
                       int s, int e, int idx) 
    {
  
        // s = starting index
        // e = ending index
        // a = array storing binary string of numbers
        // idx = starting index = 1, for recurring the tree
        if (s == e) 
        {
  
            // store each element value at the
            // leaf node
            tree[idx] = a[s];
            return;
        }
  
        int mid = (s + e) / 2;
  
        // Recurring in two sub portions (left, right)
        // to build the segment tree
  
        // Calling for the left sub portion
        buildTree(tree, a, s, mid, 2 * idx);
  
        // Calling for the right sub portion
        buildTree(tree, a, mid + 1, e, 2 * idx + 1);
  
        // Summing up the number of one's
        tree[idx] = tree[2 * idx] + tree[2 * idx + 1];
  
        return;
    }
  
    // Function to return the index of the query
    static int queryTree(int[] tree, int s, 
                        int e, int k, int idx) 
    {
  
        // s = starting index
        // e = ending index
        // k = searching for kth bit
        // idx = starting index = 1, for recurring the tree
  
        // k > number of 1's in a binary string
        if (k > tree[idx])
            return -1;
  
        // leaf node at which kth 1 is stored
        if (s == e)
            return s;
        int mid = (s + e) / 2;
  
        // If left sub-tree contains more or equal 1's
        // than required kth 1
        if (tree[2 * idx] >= k)
            return queryTree(tree, s, mid, k, 2 * idx);
  
        // If left sub-tree contains less 1's than
        // required kth 1 then recur in the right sub-tree
        else
            return queryTree(tree, mid + 1, e, k - tree[2 * idx],
                                                    2 * idx + 1);
    }
  
    // Function to perform the update query
    static void updateTree(int[] tree, int s, int e, 
                            int i, int change, int idx)
    {
  
        // s = starting index
        // e = ending index
        // i = index at which change is to be done
        // change = new changed bit
        // idx = starting index = 1, for recurring the tree
  
        // Out of bounds request
        if (i < s || i > e)
        {
            System.out.println("Error");
            return;
        }
  
        // Leaf node of the required index i
        if (s == e)
        {
  
            // Replacing the node value with
            // the new changed value
            tree[idx] = change;
            return;
        }
  
        int mid = (s + e) / 2;
  
        // If the index i lies in the left sub-tree
        if (i >= s && i <= mid)
            updateTree(tree, s, mid, i, change, 2 * idx);
  
        // If the index i lies in the right sub-tree
        else
            updateTree(tree, mid + 1, e, i, change, 2 * idx + 1);
  
        // Merging both left and right sub-trees
        tree[idx] = tree[2 * idx] + tree[2 * idx + 1];
        return;
    }
  
    // Function to perform queries
    static void queries(int[] tree, int[] a, int q, int p, 
                                int k, int change, int n) 
    {
        int s = 0, e = n - 1, idx = 1;
        if (q == 1) 
        {
  
            // q = 1 update, p = index at which change
            // is to be done, change = new bit
            a[p] = change;
            updateTree(tree, s, e, p, change, idx);
            System.out.println("Array after updation:");
            for (int i = 0; i < n; i++)
                System.out.print(a[i] + " ");
            System.out.println();
        } 
        else 
        {
  
            // q = 0, print kth bit
            System.out.printf("Index of %dth set bit: %d\n", 
                                k, queryTree(tree, s, e, k, idx));
        }
    }
  
    // Driver Code
    public static void main(String[] args) 
    {
        int[] a = { 1, 0, 1, 0, 0, 1, 1, 1 };
        int n = a.length;
  
        // Declaring & initializing the tree with
        // maximum possible size of the segment tree
        // and each value initially as 0
        int[] tree = new int[4 * n + 1];
        for (int i = 0; i < 4 * n + 1; ++i) 
        {
            tree[i] = 0;
        }
  
        // s and e are the starting and ending
        // indices respectively
        int s = 0, e = n - 1, idx = 1;
  
        // Build the segment tree
        buildTree(tree, a, s, e, idx);
  
        // Find index of kth set bit
        int q = 0, p = 0, change = 0, k = 4;
        queries(tree, a, q, p, k, change, n);
  
        // Update query
        q = 1;
        p = 5;
        change = 0;
        queries(tree, a, q, p, k, change, n);
    }
}
  
// This code is contributed by
// sanjeev2552

Python3

# Python3 implementation of the approach
  
# Function to build the tree
def buildTree(tree: list, a: list, 
                s: int, e: int, idx: int):
  
    # s = starting index
    # e = ending index
    # a = array storing binary string of numbers
    # idx = starting index = 1, for recurring the tree
    if s == e:
  
        # store each element value at the
        # leaf node
        tree[idx] = a[s]
        return
  
    mid = (s + e) // 2
  
    # Recurring in two sub portions (left, right)
    # to build the segment tree
  
    # Calling for the left sub portion
    buildTree(tree, a, s, mid, 2 * idx)
  
    # Calling for the right sub portion
    buildTree(tree, a, mid + 1, e, 2 * idx + 1)
  
    # Summing up the number of one's
    tree[idx] = tree[2 * idx] + tree[2 * idx + 1]
  
    return
  
# Function to return the index of the query
def queryTree(tree: list, s: int, e: int, 
            k: int, idx: int) -> int:
  
    # s = starting index
    # e = ending index
    # k = searching for kth bit
    # idx = starting index = 1, for recurring the tree
  
    # k > number of 1's in a binary string
    if k > tree[idx]:
        return -1
  
    # leaf node at which kth 1 is stored
    if s == e:
        return s
    mid = (s + e) // 2
  
    # If left sub-tree contains more or equal 1's
    # than required kth 1
    if tree[2 * idx] >= k:
        return queryTree(tree, s, mid, k, 2 * idx)
  
    # If left sub-tree contains less 1's than
    # required kth 1 then recur in the right sub-tree
    else:
        return queryTree(tree, mid + 1, e, 
                    k - tree[2 * idx], 2 * idx + 1)
  
# Function to perform the update query
def updateTree(tree: list, s: int, e: int, 
                i: int, change: int, idx: int):
  
    # s = starting index
    # e = ending index
    # i = index at which change is to be done
    # change = new changed bit
    # idx = starting index = 1, for recurring the tree
  
    # Out of bounds request
    if i < s or i > e:
        print("error")
        return
  
    # Leaf node of the required index i
    if s == e:
  
        # Replacing the node value with
        # the new changed value
        tree[idx] = change
        return
  
    mid = (s + e) // 2
  
    # If the index i lies in the left sub-tree
    if i >= s and i <= mid:
        updateTree(tree, s, mid, i, change, 2 * idx)
  
    # If the index i lies in the right sub-tree
    else:
        updateTree(tree, mid + 1, e, i, change, 2 * idx + 1)
  
    # Merging both left and right sub-trees
    tree[idx] = tree[2 * idx] + tree[2 * idx + 1]
    return
  
# Function to perform queries
def queries(tree: list, a: list, q: int, p: int, 
            k: int, change: int, n: int):
    s = 0
    e = n - 1
    idx = 1
    if q == 1:
  
        # q = 1 update, p = index at which change
        # is to be done, change = new bit
        a[p] = change
        updateTree(tree, s, e, p, change, idx)
        print("Array after updation:")
        for i in range(n):
            print(a[i], end=" ")
        print()
    else:
  
        # q = 0, print kth bit
        print("Index of %dth set bit: %d" % (k, 
                queryTree(tree, s, e, k, idx)))
  
# Driver Code
if __name__ == "__main__":
    a = [1, 0, 1, 0, 0, 1, 1, 1]
    n = len(a)
  
    # Declaring & initializing the tree with
    # maximum possible size of the segment tree
    # and each value initially as 0
    tree = [0] * (4 * n + 1)
  
    # s and e are the starting and ending
    # indices respectively
    s = 0
    e = n - 1
    idx = 1
  
    # Build the segment tree
    buildTree(tree, a, s, e, idx)
  
    # Find index of kth set bit
    q = 0
    p = 0
    change = 0
    k = 4
    queries(tree, a, q, p, k, change, n)
  
    # Update query
    q = 1
    p = 5
    change = 0
    queries(tree, a, q, p, k, change, n)
  
# This code is contributed by
# sanjeev2552

C#

// C# implementation of the approach
using System;
  
class GFG 
{
  
    // Function to build the tree
    static void buildTree(int[] tree, int[] a, 
                        int s, int e, int idx) 
    {
  
        // s = starting index
        // e = ending index
        // a = array storing binary string of numbers
        // idx = starting index = 1, for recurring the tree
        if (s == e) 
        {
  
            // store each element value at the
            // leaf node
            tree[idx] = a[s];
            return;
        }
  
        int mid = (s + e) / 2;
  
        // Recurring in two sub portions (left, right)
        // to build the segment tree
  
        // Calling for the left sub portion
        buildTree(tree, a, s, mid, 2 * idx);
  
        // Calling for the right sub portion
        buildTree(tree, a, mid + 1, e, 2 * idx + 1);
  
        // Summing up the number of one's
        tree[idx] = tree[2 * idx] + tree[2 * idx + 1];
  
        return;
    }
  
    // Function to return the index of the query
    static int queryTree(int[] tree, int s, 
                        int e, int k, int idx) 
    {
  
        // s = starting index
        // e = ending index
        // k = searching for kth bit
        // idx = starting index = 1, for recurring the tree
  
        // k > number of 1's in a binary string
        if (k > tree[idx])
            return -1;
  
        // leaf node at which kth 1 is stored
        if (s == e)
            return s;
        int mid = (s + e) / 2;
  
        // If left sub-tree contains more or equal 1's
        // than required kth 1
        if (tree[2 * idx] >= k)
            return queryTree(tree, s, mid, k, 2 * idx);
  
        // If left sub-tree contains less 1's than
        // required kth 1 then recur in the right sub-tree
        else
            return queryTree(tree, mid + 1, 
                            e, k - tree[2 * idx],
                            2 * idx + 1);
    }
  
    // Function to perform the update query
    static void updateTree(int[] tree, int s, int e, 
                            int i, int change, int idx)
    {
  
        // s = starting index
        // e = ending index
        // i = index at which change is to be done
        // change = new changed bit
        // idx = starting index = 1, for recurring the tree
  
        // Out of bounds request
        if (i < s || i > e)
        {
            Console.WriteLine("Error");
            return;
        }
  
        // Leaf node of the required index i
        if (s == e)
        {
  
            // Replacing the node value with
            // the new changed value
            tree[idx] = change;
            return;
        }
  
        int mid = (s + e) / 2;
  
        // If the index i lies in the left sub-tree
        if (i >= s && i <= mid)
            updateTree(tree, s, mid, i, 
                        change, 2 * idx);
  
        // If the index i lies in the right sub-tree
        else
            updateTree(tree, mid + 1, e, i,
                       change, 2 * idx + 1);
  
        // Merging both left and right sub-trees
        tree[idx] = tree[2 * idx] + 
                    tree[2 * idx + 1];
        return;
    }
  
    // Function to perform queries
    static void queries(int[] tree, int[] a, int q, int p, 
                                int k, int change, int n) 
    {
        int s = 0, e = n - 1, idx = 1;
        if (q == 1) 
        {
  
            // q = 1 update, p = index at which change
            // is to be done, change = new bit
            a[p] = change;
            updateTree(tree, s, e, p, change, idx);
            Console.WriteLine("Array after updation:");
            for (int i = 0; i < n; i++)
                Console.Write(a[i] + " ");
            Console.WriteLine();
        } 
        else
        {
  
            // q = 0, print kth bit
            Console.Write("Index of {0}th set bit: {1}\n", 
                            k, queryTree(tree, s, e, k, idx));
        }
    }
  
    // Driver Code
    public static void Main(String[] args) 
    {
        int[] a = { 1, 0, 1, 0, 0, 1, 1, 1 };
        int n = a.Length;
  
        // Declaring & initializing the tree with
        // maximum possible size of the segment tree
        // and each value initially as 0
        int[] tree = new int[4 * n + 1];
        for (int i = 0; i < 4 * n + 1; ++i) 
        {
            tree[i] = 0;
        }
  
        // s and e are the starting and ending
        // indices respectively
        int s = 0, e = n - 1, idx = 1;
  
        // Build the segment tree
        buildTree(tree, a, s, e, idx);
  
        // Find index of kth set bit
        int q = 0, p = 0, change = 0, k = 4;
        queries(tree, a, q, p, k, change, n);
  
        // Update query
        q = 1;
        p = 5;
        change = 0;
        queries(tree, a, q, p, k, change, n);
    }
}
  
// This code is contributed by Rajput-Ji

输出：

Index of 4th set bit: 6
Array after updation:
1 0 1 0 0 0 1 1