📜  Java程序查找矩阵的转置

📅  最后修改于: 2020-09-26 19:29:03             🧑  作者: Mango

在此程序中,您将学习查找并打印Java中给定矩阵的转置。

矩阵的转置是将行交换为列的过程。对于2x3矩阵,

Matrix
a11    a12    a13
a21    a22    a23

Transposed Matrix
a11    a21
a12    a22
a13    a23
示例:查找矩阵转置的程序
public class Transpose {

    public static void main(String[] args) {
        int row = 2, column = 3;
        int[][] matrix = { {2, 3, 4}, {5, 6, 4} };

        // Display current matrix
        display(matrix);

        // Transpose the matrix
        int[][] transpose = new int[column][row];
        for(int i = 0; i < row; i++) {
            for (int j = 0; j < column; j++) {
                transpose[j][i] = matrix[i][j];
            }
        }

        // Display transposed matrix
        display(transpose);
    }

    public static void display(int[][] matrix) {
        System.out.println("The matrix is: ");
        for(int[] row : matrix) {
            for (int column : row) {
                System.out.print(column + "    ");
            }
            System.out.println();
        }
    }
}

输出

The matrix is:
2    3    4    
5    6    4    
The matrix is:
2    5    
3    6    
4    4    

在上面的程序中, display() 函数仅用于将矩阵的内容打印到屏幕上。

在此,给定矩阵的形式为2x3 ,即row = 2column = 3

对于转置矩阵,我们将转置顺序更改为3x2 ,即row = 3column = 2 。因此,我们有transpose = int[column][row]

矩阵的转置是通过简单地将列交换为行来计算的:

transpose[j][i] = matrix[i][j];