📜  Python中的 numpy.minimum()

📅  最后修改于: 2022-05-13 01:54:42.288000             🧑  作者: Mango

Python中的 numpy.minimum()

numpy.minimum()函数用于查找数组元素的元素最小值。

它比较两个数组并返回一个包含元素最小值的新数组。如果要比较的元素之一是 NaN,则返回该元素。如果两个元素都是 NaN,则返回第一个。

代码#1:工作

# Python program explaining
# minimum() function
  
import numpy as geek
in_num1 = 10
in_num2 = 21
  
print ("Input  number1 : ", in_num1)
print ("Input  number2 : ", in_num2) 
    
out_num = geek.minimum(in_num1, in_num2) 
print ("minimum of 10 and 21 : ", out_num) 

输出 :

Input  number1 :  10
Input  number2 :  21
minimum of 10 and 21 :  10


代码#2:

# Python program explaining
# minimum() function
  
import numpy as geek
  
in_arr1 = [2, 8, 125]
in_arr2 = [3, 3, 15]
   
print ("Input array1 : ", in_arr1) 
print ("Input array2 : ", in_arr2)
    
out_arr = geek.minimum(in_arr1, in_arr2) 
print ("Output array after selecting minimum: ", out_arr) 

输出 :

Input array1 :  [2, 8, 125]
Input array2 :  [3, 3, 15]
Output array after selecting minimum:  [ 2  3 15]


代码#3:

# Python program explaining
# minimum() function
  
import numpy as geek
  
in_arr1 = [geek.nan, 0, geek.nan]
in_arr2 = [geek.nan, geek.nan, 0]
   
print ("Input array1 : ", in_arr1) 
print ("Input array2 : ", in_arr2)
    
out_arr = geek.minimum(in_arr1, in_arr2) 
print ("Output array after selecting minimum: ", out_arr) 

输出 :

Input array1 :  [nan, 0, nan]
Input array2 :  [nan, nan, 0]
Output array after selecting minimum:  [ nan  nan  nan]