检查是否可以创建具有给定角度的多边形

给定角度$a$在哪里， $1\le a< 180$ 。任务是检查是否有可能制作一个规则多边形，使其所有内角等于$a$ 。如果可能，然后打印“是”，否则打印“否”(不带引号)。
例子：

Input: angle = 90
Output: YES
Polygons with sides 4 is
possible with angle 90 degrees.

Input: angle = 30
Output: NO

方法：内角定义为规则多边形的任意两个相邻边之间的角度。
它是由$\;Interior\;angle = \frac{180 \times (n-2)}{n}\;$其中， n是多边形中的边数。
这可以写成$\;a = \frac{180 \times (n-2)}{n}\;$ 。
经过重新安排，我们得到了， $\;n = \frac{360}{180 - a}\;$ 。
因此，如果n为整数，则答案为“是”，否则答案为“否”。

下面是上述方法的实现：

C++

// C++ implementation of above approach
#include 
using namespace std;
  
// Function to check whether it is possible
// to make a regular polygon with a given angle.
void makePolygon(float a)
{
    // N denotes the number of sides
    // of polygons possible
    float n = 360 / (180 - a);
    if (n == (int)n)
        cout << "YES";
    else
        cout << "NO";
}
  
// Driver code
int main()
{
    float a = 90;
  
    // function to print the required answer
    makePolygon(a);
  
    return 0;
}

Java

class GFG 
{
// Function to check whether 
// it is possible to make a
// regular polygon with a given angle. 
static void makePolygon(double a) 
{ 
    // N denotes the number of 
    // sides of polygons possible 
    double n = 360 / (180 - a); 
    if (n == (int)n) 
        System.out.println("YES"); 
    else
        System.out.println("NO"); 
} 
  
// Driver code 
public static void main (String[] args) 
{
    double a = 90; 
  
    // function to print
    // the required answer 
    makePolygon(a); 
}
}
  
// This code is contributed by Bilal

Python3

# Python 3 implementation 
# of above approach 
  
# Function to check whether 
# it is possible to make a
# regular polygon with a 
# given angle. 
def makePolygon(a) :
  
    # N denotes the number of sides 
    # of polygons possible
    n = 360 / (180 - a)
  
    if n == int(n) :
        print("YES")
  
    else :
        print("NO")
  
# Driver Code
if __name__ == "__main__" :
    a = 90
  
    # function calling 
    makePolygon(a)
      
# This code is contributed 
# by ANKITRAI1

C#

// C# implementation of 
// above approach
using System;
  
class GFG 
{
// Function to check whether 
// it is possible to make a
// regular polygon with a 
// given angle. 
static void makePolygon(double a) 
{ 
    // N denotes the number of 
    // sides of polygons possible 
    double n = 360 / (180 - a); 
    if (n == (int)n) 
        Console.WriteLine("YES"); 
    else
        Console.WriteLine("NO"); 
} 
  
// Driver code 
static void Main() 
{
    double a = 90; 
  
    // function to print
    // the required answer 
    makePolygon(a); 
}
}
  
// This code is contributed by mits

输出：

YES