在给定周长下可能的矩形最大面积

给定矩形的周长，任务是找到可以使用n单位长度作为其周长的矩形的最大面积。

注意：“长度”和“宽度”必须是整数值。

例子：

Input: perimeter = 15
Output: Maximum Area = 12

Input: perimeter = 16
Output: Maximum Area = 16

方法：要使任何矩形的面积最大，长度和宽度的差必须最小。因此，在这种情况下，长度必须为ceil(周长/ 4)，而宽度应为地板(周长/ 4)。因此，具有给定周长的矩形的最大面积等于ceil(perimeter / 4)* floor(perimeter / 4) 。

下面是上述方法的实现：

C++

// C++ to find maximum area rectangle
#include 
using namespace std;
 
// Function to find max area
int maxArea(float perimeter)
{
    int length = (int)ceil(perimeter / 4);
    int breadth = (int)floor(perimeter / 4);
 
    // return area
    return length * breadth;
}
 
// Driver code
int main()
{
    float n = 38;
    cout << "Maximum Area = " << maxArea(n);
 
    return 0;
}

Java

//Java to find maximum area rectangle
 
import java.io.*;
 
class GFG {
// Function to find max area
static int maxArea(float perimeter)
{
    int length = (int)Math.ceil(perimeter / 4);
    int breadth = (int)Math.floor(perimeter / 4);
 
// return area
return length * breadth;
}
 
// Driver code
     
    public static void main (String[] args) {
 
        float n = 38;
        System.out.println("Maximum Area = " +
                maxArea(n));
         
    }
}

Python3

# Python3 program to find
# maximum area rectangle
from math import ceil, floor
 
# Function to find max area
def maxArea(perimeter):
    length = int(ceil(perimeter / 4))
    breadth = int(floor(perimeter / 4))
 
    # return area
    return length * breadth
 
# Driver code
if __name__ == '__main__':
    n = 38
    print("Maximum Area =", maxArea(n))

C#

// C# to find maximum area rectangle
using System;
 
class GFG
{
// Function to find max area
static int maxArea(float perimeter)
{
    int length = (int)Math.Ceiling(perimeter / 4);
    int breadth = (int)Math.Floor(perimeter / 4);
 
    // return area
    return length * breadth;
}
 
// Driver code
public static void Main()
{
    float n = 38;
    Console.WriteLine("Maximum Area = " +
                             maxArea(n));
}
}
 
// This code is contributed
// by Akanksha Rai(Abby_akku)

Javascript

 
// JavaScript to find maximum area rectangle
 
// Function to find max area
function maxArea(perimeter)
{
    let length = Math.ceil(perimeter / 4);
    let breadth = Math.floor(perimeter / 4);
 
    // return area
    return length * breadth;
}
 
// Driver code
let n = 38;
 
document.write("Maximum Area = " + maxArea(n));
 
// This code is contributed by Manoj.
 

输出：

Maximum Area = 90