Java中的 StrictMath pow() 方法
Java.lang.StrictMath.pow()是StrictMath 类的内置方法,用于查找幂值,即一个参数的值提升到另一个参数的幂。数学上指的是 .它产生了三个特殊的结果:
- 当一个参数是 NaN 而另一个是非零参数或 NaN 时,该方法返回 NaN。
- 当第二个参数为 1.0 时,该方法返回与第一个参数相同的值。
- 当第二个参数为正零或负零时,该方法返回 1.0。
句法:
public static double pow(double num1, double num2)
参数:该方法接受两个参数:
- num1:这是双精度类型,是指基数。
- num2:这是双精度类型,指的是指数。
返回值:该方法返回操作num1^num2的值。
例子 :
Input: num1 = 6
num2 = 4
Output: 1296.0
Input: num1 = 5
num2 = 2
Output: 25.0
下面的程序说明了Java.lang.StrictMath.pow() 方法:
方案一:
java
// Java program to illustrate the
// java.lang.StrictMath.pow()
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 12, num2 = 6;
// It returns num1 to the power num2
double pow_Value = StrictMath.pow(num1, num2);
System.out.print(num1 + " to the power of " +
num2 + " = ");
System.out.println(pow_Value);
double pow_Value1 = StrictMath.pow(num1, 0);
double pow_Value2 = StrictMath.pow(num1, 0);
System.out.println(num1+" raised to the"+
" power 0 = " + pow_Value1);
System.out.println(num2+" raised to the"+
" power 0 = " + pow_Value2);
}
}
java
// Java program to illustrate the
// java.lang.StrictMath.pow()
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 4.7, num2 = 2.5;
// It returns num1 to the power num2
double pow_Value = StrictMath.pow(num1, num2);
System.out.print(num1 + " to the power of " +
num2 + " = ");
System.out.println(pow_Value);
}
}
输出:
12.0 to the power of 6.0 = 2985984.0
12.0 raised to the power 0 = 1.0
6.0 raised to the power 0 = 1.0
方案二:
Java
// Java program to illustrate the
// java.lang.StrictMath.pow()
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 4.7, num2 = 2.5;
// It returns num1 to the power num2
double pow_Value = StrictMath.pow(num1, num2);
System.out.print(num1 + " to the power of " +
num2 + " = ");
System.out.println(pow_Value);
}
}
输出:
4.7 to the power of 2.5 = 47.88997880559147