📜  Python中的 numpy.logical_xor()

📅  最后修改于: 2022-05-13 01:55:02.104000             🧑  作者: Mango

Python中的 numpy.logical_xor()

numpy.logical_xor(arr1, arr2, out=None, where = True, cast = 'same_kind', order = 'K', dtype = None, ufunc 'logical_xor') :这是一个逻辑函数,它可以帮助用户找出arr1 XOR arr2 element-wise 的真值。两个阵列必须具有相同的形状。

参数 :

返回 :

An array with Boolean results of arr1 XOR arr2 element-wise(of the same shape).  


代码 1:工作

# Python program explaining
# logical_xor() function
import numpy as np
  
# input
arr1 = [1, 3, False, 0]
arr2 = [3, 0, True, False]
  
# output
out_arr = np.logical_xor(arr1, arr2)
  
print ("Output Array : ", out_arr)

输出 :

Output Array :  [False  True  True False]


代码 2:如果输入数组的形状不同,则值错误

# Python program explaining
# logical_xor() function
import numpy as np
  
# input
arr1 = [8, 2, False, 4]
arr2 = [3, 0, False, False, 8]
  
# output
out_arr = np.logical_xor(arr1, arr2)
  
print ("Output Array : ", out_arr)

输出 :

ValueError: operands could not be broadcast together with shapes (4,) (5,)  


代码3:可以检查条件

# Python program explaining
# logical_xor() function
import numpy as np
  
# input
arr1 = np.arange(8)
print ("arr1 : ", arr1)
  
print ("\narr1>3 : \n", arr1>3)
print ("\narr1<6 : \n", arr1<6)
  
print ("\nXOR Value  : \n", np.logical_xor(arr1>3, arr1<6))

输出 :

arr1 :  [0 1 2 3 4 5 6 7]

arr1>3 : 
 [False False False False  True  True  True  True]

arr1<6 : 
 [ True  True  True  True  True  True False False]

XOR Value  : 
 [ True  True  True  True False False  True  True]

参考 :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.logical_xor.html#numpy.logical_xor
.