给定链表的成对交换元素的 C# 程序
给定一个单链表,编写一个函数来成对交换元素。
Input: 1->2->3->4->5->6->NULL Output: 2->1->4->3->6->5->NULL
Input: 1->2->3->4->5->NULL Output: 2->1->4->3->5->NULL
Input: 1->NULL Output: 1->NULL
例如,如果链表是 1->2->3->4->5,则函数应将其更改为 2->1->4->3->5,如果链表是函数应将其更改为。
方法1(迭代):
从头节点开始,遍历列表。在遍历每个节点的交换数据及其下一个节点的数据时。
下面是上述方法的实现:
C#
// C# program to pairwise swap elements
// of a linked list
using System;
class LinkedList
{
// Head of list
Node head;
// Linked list Node
public class Node
{
public int data;
public Node next;
public Node(int d)
{
data = d;
next = null;
}
}
void pairWiseSwap()
{
Node temp = head;
/* Traverse only till there are
atleast 2 nodes left */
while (temp != null &&
temp.next != null)
{
// Swap the data
int k = temp.data;
temp.data = temp.next.data;
temp.next.data = k;
temp = temp.next.next;
}
}
// Utility functions
/* Inserts a new Node at front
of the list. */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);
// 3. Make next of new Node as head
new_node.next = head;
/* 4. Move the head to point to
new Node */
head = new_node;
}
// Function to print linked list
void printList()
{
Node temp = head;
while (temp != null)
{
Console.Write(temp.data + " ");
temp = temp.next;
}
Console.WriteLine();
}
// Driver code
public static void Main(String[] args)
{
LinkedList llist = new LinkedList();
/* Created Linked List
1->2->3->4->5 */
llist.push(5);
llist.push(4);
llist.push(3);
llist.push(2);
llist.push(1);
Console.WriteLine(
"Linked List before calling pairWiseSwap() ");
llist.printList();
llist.pairWiseSwap();
Console.WriteLine(
"Linked List after calling pairWiseSwap() ");
llist.printList();
}
}
// This code is contributed by Arnab Kundu
C#
/* Recursive function to pairwise swap
elements of a linked list */
static void pairWiseSwap(node head)
{
/* There must be at-least two nodes
in the list */
if (head != null &&
head.next != null)
{
/* Swap the node's data with data
of next node */
swap(head.data, head.next.data);
/* Call pairWiseSwap() for rest
of the list */
pairWiseSwap(head.next.next);
}
}
// This code is contributed by aashish1995
输出:
Linked list before calling pairWiseSwap()
1 2 3 4 5
Linked list after calling pairWiseSwap()
2 1 4 3 5
时间复杂度: O(n)
方法 2(递归):
如果链接列表中有 2 个或超过 2 个节点,则交换前两个节点并递归调用列表的其余部分。
下图是上述方法的试运行:
下面是上述方法的实现:
C#
/* Recursive function to pairwise swap
elements of a linked list */
static void pairWiseSwap(node head)
{
/* There must be at-least two nodes
in the list */
if (head != null &&
head.next != null)
{
/* Swap the node's data with data
of next node */
swap(head.data, head.next.data);
/* Call pairWiseSwap() for rest
of the list */
pairWiseSwap(head.next.next);
}
}
// This code is contributed by aashish1995
时间复杂度: O(n)
那里提供的解决方案交换节点的数据。如果数据包含很多字段,就会有很多交换操作。有关更改链接而不是交换数据的实现,请参阅此内容。
有关详细信息,请参阅有关给定链表的成对交换元素的完整文章!