集中趋势是指识别给定数据集的中心位置。集中趋势具有3个重要度量，即均值，中位数和众数。学生们在他们每个人之间都困惑了好几次。因此，在这里，我们将借助示例解释这三个示例之间的差异。
平均值：平均值，这里的算术平均值是最常用的集中趋势度量。对于离散数据集和连续数据集，都可以获得平均值。要获得一组数字的平均值，您必须对所有数字求和，然后使用总数除。简而言之，它计算出所有数字的平均值。也可以说，它是所有观察值之和与观察值总数之比。在学前班中，它是作为平均水平向学生介绍的，而在高年级中，我们知道它也被称为平均数。
中位数：当您将一组给定的数字从小到大排列时，中间的数字称为中位数。以升序或降序排列任何给定的序列，或者将中间值称为中位数。为了找到中位数，可以按降序或升序排列数据。在几何中，它定义为多边形的中心或中点。
模式：在给定的一组观测值中重复次数最多的数字是模式，或者也可以说是在给定的一系列数字中频率最高的数字或值。也称为模态值。它是除中位数和均值之外的3个中心趋势的一部分。如果以直方图或图表形式显示，则它是最高的条。如果给定系列中没有重复编号，则该系列将不存在任何模式。
均值，中位数和众数之间的差异表
所有这些集中趋势的度量都是相互关联的。它们具有经验关系，但彼此不同。区别如下：
| S.No | Mean | Median | Mode |
| 1 | The average taken of given observations is called Mean. | The middle number in a given set of observations is called Median. | The most frequently occurred number in a given set of observations is called mode. |
| 2 | Add up all the numbers and divide by the total number of terms | Place all the numbers in ascending or descending order | the mode is derived when a number has frequency occurred in a series |
| 3 | Once the above step is finished, what we get is the mean. | After arranging everything from smallest to biggest, take out the middle number, which is your median. | The mode can be one or more than one. It is possible to have no mode at all, as well |
| 4 | Mean is the arithmetic mean or in a simple way can be a simple average or weighted average. | When series have even numbers, median is the simple average of the middle pair of numbers. If there is a unique data set, there is no mode at all. | If there is a unique data set, there is no mode at all. |
| 5 | When data is normally distributed, the mean is widely preferred. | When data distribution is skewed, median is the best representative. | When there is a nominal distribution of data, the mode is preferred. |
| 6 | Mean= x̄ = ∑x/ N |
If the total number of observations (n) are odd then median is: Median = (n + 1/2)th observation If the total number of observations (n) are even number, then the formula is given below: Median = (n/2)th observation + (n/2+1)th observation /2 |
The mode is the most frequently occurring observation or value |
中心倾向样本问题
问题1：我们有一组数字，分别为4、8、2、1、1、4、3、1。找到均值，中位数和众数。
解决方案：
Mean:
8 + 4 + 2 + 1 + 1 + 4 + 3 + 1 = 24 and 24/8 = 3
Median:
2 + 3/2 = 5.2 (after arranging the numbers in ascending order as 1, 1, 1, 2, 3, 4, 4, 8 and middle terms are 2 and 3 as total number of terms are 8 which is even)
Mode:
1 because it is present 3 times in the sequence
问题2：我们有一组数字，分别是4、2、1、6、5、3、7、1、10、9、8。找到均值，中位数和众数。
解决方案：
Mean:
1+1+2+3+4+5+6+7+8+9+10 = 56 and 56/10 = 5.6
Median:
5 (after arranging in ascending order 1,1,2,3,4,5,6,7,8,9,10 the middle term is 5)
Mode:
1 {as it is repeated the highest number of times(2 times)}.