问题1.查找：
(i)120％的22％
(ii)1000卢比的25％
(iii)10公斤的25％
(iv)5000米的16.5％
(v)80厘米的135％
(vi)10000毫升的2.5％
解决方案：
(i) 22% of 120
22% of 120 can be termed as (22/100) X 120 = 26.4
(ii) 25% of Rs 1000
25% of Rs 1000 can be termed as (25/100) X 1000 = Rs 250
(iii) 25% of 10 kg
25% of 10 kg can be termed as (25/100) X 10 = 2.5 kg
(iv) 16.5% of 5000 metre
16.5% of 5000 metre can be termed as (16.5/100) X 5000 = 825 metre
(v) 135% of 80 cm
135% of 80 cm can be termed as (135/100) X 80 = 108 cm
(vi) 2.5% of 10000 ml
2.5% of 10000 ml can be termed as (2.5/100) X 10000 = 250 ml
问题2。找到数字“ a”，如果
(i)a的8.4％为42
(ii)a的0.5％为3
(iii)a的1/2％为50
(iv)a的100％为100
解决方案：
(i) Given, 8.4% of a is 42
So, (8.4/100) × a = 42
a = 4200/8.4 = 500
Hence, a = 500
(ii) Given, 0.5% of a is 3
So, (0.5/100) × a = 3
a = 300/0.5 = 600
Hence, a = 600
(iii) Given, 1/2 % of a is 50
So, (0.5/100) × a = 50
a = 5000/0.5 = 10000
Hence, a = 10000
(iv) Given, 100% of a is 100
So, (100/100) × a = 100
a = 100
Hence, a = 100
问题3。x是y的5％，y是z的24％。如果x = 480，则找到y和z的值。
解决方案：
Given, x is 5% of y
y is 24% of z
x = 480
Since, x = 5% of y
We can write, 480 = 5% of y
So, 480 = (5/100) × y
y = 9600
Also, y = 24% of z
So, 9600 = (24/100) × z
z = 40000
Hence, y is 9600 and z is 40000
问题4.苦力存卢比。每月在他的邮局储蓄银行帐户中支付150。如果这是他每月收入的15％，请找到他的每月收入。
解决方案：
Let a be the monthly income of coolie
Given, a coolie deposits Rs. 150 per month in his post and this is equal to 15% of his monthly income
So, 15 % of a = Rs 150
(15/100) × a = 150
a = Rs 1000
Hence, the monthly income of coolie is Rs 1000
问题5：阿莎(Asha)在年度考试中获得了86.875％的分数。如果她获得695分，请找到考试的分数。
解决方案：
Let a be the total number of marks in the Exam
Given, marks scored by Asha is 695 and this is 86.875% marks
So, 86.875% of a = 695
(86.875/100) × a = 695
a = 800 marks
Hence, the examination is of 800 marks
问题6. Deepti一年要上学216天。如果她的出勤率为90％，请问学校开学的天数是多少?
解决方案：
Given, Number of days Deepti went to school is 216 and this is 90 % of her attendance
Let a be the total number of days, the school was opened.
So, 90 % of a = 216
(90/100) × a = 216
a = 240 days
Hence, the school was opened for 240 days
问题7.一个花园有2000棵树。其中12％是芒果树，18％柠檬是柠檬树，其余的是橘子树。查找橘子树的数量。
解决方案：
Given, the total number of trees = 2000
12% of these are mango trees, 18% lemon and the rest are orange trees
So, 12 % of 2000 are mango trees
12 % of 2000 = Number of Mango trees
Number of Mango trees = (12/100) × 2000 = 240 trees
Number of Lemon trees = 18 % of 2000 = (18/100) × 2000 = 360 trees
And, the number of Orange trees = Total number of trees — (Number of Mango trees+ Number of Lemon trees)
= 2000 – (240 + 360) = 1400
Hence, there are 1400 orange trees in the garden
问题8.均衡饮食应包含12％的蛋白质，25％的脂肪和63％的碳水化合物。如果孩子每天需要2600卡路里的这种食物，则应从其日常食物摄入量中找到其中每一个的卡路里含量。
解决方案：
Given, total amount of calories needed = 2600
So, the amount of Protein needed = 12 % of 2600
= (12/100) × 2600 = 312 calories
The amount of Fats needed = 25 % of 2600
= (25/100) × 2600 = 650 calories
The amount of Carbohydrate needed = 63 % of 2600
= (63/100) × 2600 = 1638 calories
Hence, the amount of calories needed in Protein, Fats and Carbohydrate is 312, 650 and 1638 calories respectively
问题9.板球运动员总共打了96球，总共得分62次。他打出3个6、8个4、2个2和8个单打。占总运行次数的百分比：
(i)六
(ii)四肢
(iii)二
(iv)单身
解决方案：
Given, a cricketer scored a total of 62 runs in 96 balls
i) The total runs scored in form of Sixes = 3 × 6 = 18
So, percentage of runs scored in form of Sixes = (18/62) × 100 = 29.03%
ii) The total runs scored in form of Fours = 8 × 4 = 32
So, percentage of runs scored in form of Fours = (32/62) × 100 = 51.61%
iii) The total runs scored in form of Twos = 2 × 2 = 4
So, percentage of runs scored in form of Twos = (4/62) × 100 = 6.45%
iv) The total runs scored in form of Singles = 1 × 8 = 8
So, percentage of runs scored in form of Singles = (8/62) × 100 = 12.9%
问题10.板球运动员在一场测试比赛中以150个球击中120球。 20％的成绩是6分，30％的是4分，25％的是2分，其余的是1分。他得分了多少次：
(i)6
(ii)4
(iii)2
(iv)单身
他的投篮命中率是多少?
解决方案：
Given, a cricketer hits 120 runs in 150 balls
i) Number of runs scored in form of 6’s = 20 % of 120
= (20/100) × 120 = 24 runs
ii) Number of runs scored in form of 4’s = 30 % of 120
= (30/100) × 120 = 36 runs
iii) Number of runs scored in form of 2’s = 25 % of 120
= (25/100) × 120 = 30 runs
iv) Number of runs scored in form of singles = 120 – (24 + 36 + 30) = 30 runs
Now, the percentage of runs scored in singles = (30/100) × 120 = 25%
Hence, 25 % of runs scored in form of singles
问题11：拉达(Radha)赚了她投资的22％。如果她能赚到卢比。 187，那她投入了多少?
解决方案：
Given, the amount of money Radha earned through investment = Rs 187
Let a be the amount of money she invested
So, we can say that 22 % of a = 187
(22/100) × a = 187
a = Rs 850
Hence, Radha invested Rs 850
问题12.罗希特(Rohit)将其收入的12％存入银行。他存入卢比。在1997年期间，他在银行的收入为1440。1997年他的总收入是多少?
解决方案：
Given, Rohit deposits 12% of his income in a bank.
Let a be the total income of Rohit in year 1997
So, we can say 12 % of a = 1440
(12/100) × a = 1440
a = Rs 12000
Hence, the total income of Rohit in year 1997 is Rs 12000
问题13.火药含有75％的硝态氮和10％的硫。找到携带9千克硝态氮的火药数量。多少火药中将含有2.3千克硫磺?
解决方案：
Given, Gunpowder contains 75% nitre and 10% sulphur
Let a be the total amount of gunpowder
i) So, we can say 75 % of a = 9 kg Nitre
(75/100) × a = 9
a = 12 kg
Hence, 12 kg gunpowder carries 9 kg nitre
ii) So, we can say 10 % of a = 2.3 kg Sulphur
(10/100) × a = 2.3
a = 23 kg
Hence, 23 kg gunpowder carries 2.3 kg sulphur