RC4是一种对称流密码和可变密钥长度算法。此对称密钥算法被相同地用于加密和解密，以便将数据流与生成的密钥序列进行简单的XOR运算。该算法是串行的，因为它需要根据密钥序列进行状态条目的连续交换。该算法分为两个阶段：
密钥调度算法(KSA) ：
- 通过使用由0到256个字节组成的可变长度密钥应用置换来生成状态数组。
- 状态向量被标识为S [0] ， S [1]…。 S [255]用{0，1，2，…，255}初始化。密钥K [0] ， K [1]，….，K [255]的长度可以从0到256个字节，用于初始化置换S。每个K [I]和S [I]是一个字节。
- 如果密钥的长度为256个字节，则K是一个临时数组，将其复制到K，否则在复制K的其余位置后，将重复的Key Value填充到K的剩余位置，直到充满。
S[] is permutation of 0, 1, ..., 255
key[] contains N bytes of key
for i = 0 to 255
S[i] = i
// Selects a keystream byte from
// the table
K[i] = key[i (mod N)]
i++
j = 0
for i = 0 to 255
j = (j + S[i] + K[i]) mod 256
// Swaps elements in the current
// lookup table
swap(S[i], S[j])
i = j = 0伪随机数生成算法(PRGA) ：用于在经过一轮置换后从状态向量数组生成密钥流字节。
Keystream Generation(i := 0, j := 0 )
while Generating Output:
i = (i + 1) mod 256
j = (j + S[i]) mod 256
swap(S[i], S[j])
t = (S[i] + S[j]) mod 256
keystreamByte = S[t]
At each iteration, swap elements in table
and select keystream byte然后，在生成的密钥流和用于加密的纯文本之间执行XOR。
请按照与上述相同的步骤进行解密，并在各处使用密文代替明文。
例子：
Input: plain text = 001010010010, key = 101001000001, n= 3
Output:
cipher text = 110011100011
decrypted text = 001010010010
Input: plain text = 1111000000001111, key = 0101010111001010, n= 4
Output:
cipher text = 0011011110100010
decrypted text = 1111000000001111
以下是上述方法的实现，并详细输出了涉及的所有重要步骤：
Python3
# Python3 program for the above approach
# of RC4 algorithm
# Function for encryption
def encryption():
global key, plain_text, n
# Given text and key
plain_text = "001010010010"
key = "101001000001"
# n is the no: of bits to
# be considered at a time
n = 3
print("Plain text : ", plain_text)
print("Key : ", key)
print("n : ", n)
print(" ")
# The initial state vector array
S = [i for i in range(0, 2**n)]
print("S : ", S)
key_list = [key[i:i + n] for i in range(0, len(key), n)]
# Convert to key_stream to decimal
for i in range(len(key_list)):
key_list[i] = int(key_list[i], 2)
# Convert to plain_text to decimal
global pt
pt = [plain_text[i:i + n] for i in range(0, len(plain_text), n)]
for i in range(len(pt)):
pt[i] = int(pt[i], 2)
print("Plain text ( in array form ): ", pt)
# Making key_stream eqaul
# to length of state vector
diff = int(len(S)-len(key_list))
if diff != 0:
for i in range(0, diff):
key_list.append(key_list[i])
print("Key list : ", key_list)
print(" ")
# Perform the KSA algorithm
def KSA():
j = 0
N = len(S)
# Iterate over the range [0, N]
for i in range(0, N):
# Find the key
j = (j + S[i]+key_list[i]) % N
# Update S[i] and S[j]
S[i], S[j] = S[j], S[i]
print(i, " ", end ="")
# Print S
print(S)
initial_permutation_array = S
print(" ")
print("The initial permutation array is : ",
initial_permutation_array)
print("KSA iterations : ")
print(" ")
KSA()
print(" ")
# Perform PGRA algorithm
def PGRA():
N = len(S)
i = j = 0
global key_stream
key_stream = []
# Iterate over [0, length of pt]
for k in range(0, len(pt)):
i = (i + 1) % N
j = (j + S[i]) % N
# Update S[i] and S[j]
S[i], S[j] = S[j], S[i]
print(k, " ", end ="")
print(S)
t = (S[i]+S[j]) % N
key_stream.append(S[t])
# Print the key stream
print("Key stream : ", key_stream)
print(" ")
print("PGRA iterations : ")
print(" ")
PGRA()
# Performing XOR between generated
# key stream and plain text
def XOR():
global cipher_text
cipher_text = []
for i in range(len(pt)):
c = key_stream[i] ^ pt[i]
cipher_text.append(c)
XOR()
# Convert the encrypted text to
# bits form
encrypted_to_bits = ""
for i in cipher_text:
encrypted_to_bits += '0'*(n-len(bin(i)[2:]))+bin(i)[2:]
print(" ")
print("Cipher text : ", encrypted_to_bits)
encryption()
print("---------------------------------------------------------")
# Function for decryption of data
def decryption():
# The initial state vector array
S = [i for i in range(0, 2**n)]
key_list = [key[i:i + n] for i in range(0, len(key), n)]
# Convert to key_stream to decimal
for i in range(len(key_list)):
key_list[i] = int(key_list[i], 2)
# Convert to plain_text to decimal
global pt
pt = [plain_text[i:i + n] for i in range(0, len(plain_text), n)]
for i in range(len(pt)):
pt[i] = int(pt[i], 2)
# making key_stream eqaul
# to length of state vector
diff = int(len(S)-len(key_list))
if diff != 0:
for i in range(0, diff):
key_list.append(key_list[i])
print(" ")
# KSA algorithm
def KSA():
j = 0
N = len(S)
# Iterate over the range [0, N]
for i in range(0, N):
j = (j + S[i]+key_list[i]) % N
# Update S[i] and S[j]
S[i], S[j] = S[j], S[i]
print(i, " ", end ="")
print(S)
initial_permutation_array = S
print(" ")
print("The initial permutation array is : ",
initial_permutation_array)
print("KSA iterations : ")
print(" ")
KSA()
print(" ")
# Perform PRGA algorithm
def do_PGRA():
N = len(S)
i = j = 0
global key_stream
key_stream = []
# Iterate over the range
for k in range(0, len(pt)):
i = (i + 1) % N
j = (j + S[i]) % N
# Update S[i] and S[j]
S[i], S[j] = S[j], S[i]
print(k, " ", end ="")
print(S)
t = (S[i]+S[j]) % N
key_stream.append(S[t])
print("Key stream : ", key_stream)
print(" ")
print("PGRA iterations : ")
print(" ")
do_PGRA()
# Perform XOR between generated
# key stream and cipher text
def do_XOR():
global original_text
original_text = []
for i in range(len(cipher_text)):
p = key_stream[i] ^ cipher_text[i]
original_text.append(p)
do_XOR()
# convert the decrypted text to
# the bits form
decrypted_to_bits = ""
for i in original_text:
decrypted_to_bits += '0'*(n-len(bin(i)[2:]))+bin(i)[2:]
print(" ")
print("Decrypted text : ",
decrypted_to_bits)
# Driver Code
decryption()输出：
Plain text : 001010010010
Key : 101001000001
n : 3
S : [0, 1, 2, 3, 4, 5, 6, 7]
Plain text ( in array form ): [1, 2, 2, 2]
Key list : [5, 1, 0, 1, 5, 1, 0, 1]
KSA iterations :
0 [5, 1, 2, 3, 4, 0, 6, 7]
1 [5, 7, 2, 3, 4, 0, 6, 1]
2 [5, 2, 7, 3, 4, 0, 6, 1]
3 [5, 2, 7, 0, 4, 3, 6, 1]
4 [5, 2, 7, 0, 6, 3, 4, 1]
5 [5, 2, 3, 0, 6, 7, 4, 1]
6 [5, 2, 3, 0, 6, 7, 4, 1]
7 [1, 2, 3, 0, 6, 7, 4, 5]
The initial permutation array is : [1, 2, 3, 0, 6, 7, 4, 5]
PGRA iterations :
0 [1, 3, 2, 0, 6, 7, 4, 5]
1 [1, 3, 6, 0, 2, 7, 4, 5]
2 [1, 3, 6, 2, 0, 7, 4, 5]
3 [1, 3, 6, 2, 0, 7, 4, 5]
Key stream : [7, 1, 6, 1]
Cipher text : 110011100011
---------------------------------------------------------
KSA iterations :
0 [5, 1, 2, 3, 4, 0, 6, 7]
1 [5, 7, 2, 3, 4, 0, 6, 1]
2 [5, 2, 7, 3, 4, 0, 6, 1]
3 [5, 2, 7, 0, 4, 3, 6, 1]
4 [5, 2, 7, 0, 6, 3, 4, 1]
5 [5, 2, 3, 0, 6, 7, 4, 1]
6 [5, 2, 3, 0, 6, 7, 4, 1]
7 [1, 2, 3, 0, 6, 7, 4, 5]
The initial permutation array is : [1, 2, 3, 0, 6, 7, 4, 5]
Key stream : [7, 1, 6, 1]
PGRA iterations :
0 [1, 3, 2, 0, 6, 7, 4, 5]
1 [1, 3, 6, 0, 2, 7, 4, 5]
2 [1, 3, 6, 2, 0, 7, 4, 5]
3 [1, 3, 6, 2, 0, 7, 4, 5]
Decrypted text : 001010010010
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