TCS 安置文件 |多选题 7

这是一份用于能力准备的 TCS 模型安置论文。这份安置文件将涵盖 TCS 招聘活动中提出的能力问题，并严格遵循 TCS 面试中提出的问题模式。建议解决以下每个问题，以增加通过 TCS 面试的机会。

1. 使用相同长度的木棒形成一个三角形，如下图所示。如果用 87 根这样的棍子，那么可以形成多少个三角形？
   
   一）42
   b) 43
   c) 44
   d) 45

   Answer: b) 43

   Solution:
   As we can see the first triangle can be formed using 3 sticks. So we have 87 – 3 = 84 sticks left.
   So every next triangle can be formed using 2 sticks.
   So we have 84/2 = 42 triangles and 43 triangles in all.

2. 在 3, 12, 7, 26, 15, ?
   一）54
   b) 55
   c) 64
   d) 74

   Answer: a) 54

   Solution:
   3 * 2 + 1 = 7
   12 * 2 + 2 = 26
   7 * 2 + 1 = 15
   26 * 2 + 2 = 54

3. 有一种玩具枪可以发出 10 种音乐声。故障后发出2声乐音。相同的乐音连续发出 5 次的概率是多少？
   一）1/16
   b) 1/32
   c) 1/48
   d) 1/2

   Answer: b) 1/32

   Solution:
   The probability of making the same sound every time = 1/2,
   So, 1/2^5 = 1/32 (answer)

4. 有多少种可能的方式将 3240 写为 3 个正整数的乘积？
   一）320
   b) 420
   c) 350
   d) 450

   Answer: d) 450 ways

   Solution:
   First let’s prime factorize the number 3240 = $$2^3 * 3^4 * 5^1$$
   Let the three positive numbers be x, y and z
   We have to distribute three 2’s to x, y and z ways in (3+3-1)C(3-1) = 5C2 ways = 10 ways
   We have to distribute four 3’s to x, y, z in (3+4-1)C(3-1) = 6C2 ways
   We have to distribute one 5 to x, y, z in 3 ways.
   The total number of ways = 10×15×3=450 ways.

5. 衬衫的标价比建议零售价低 40%。 Ram 在 15 周年特卖会上以标价的一半购买了这件外套。 Ram 支付的价格比建议零售价低百分之多少？
   a) 70%
   b) 20%
   c) 60%
   d) 30%

   Answer: a) 70%

   Solution:
   Let the retail price of the shirt be Rs. 100
   So according to the question, the market price will be = 100*0.6 = 60
   Purchased price of Ram = 60/2 = 30
   which is 70% less than retail price.

6. 2472、1284和第三个数字的HCF是12。如果他们的LCM是8*9*5*103*107，那么数字是多少？
   a) 2^2*3^2*7^1
   b) 2^2*3^2*5^1
   c) 2^2*3^2*8103
   d) 以上都不是。

   Answer: b) 2^2×3^2×5^1

   Solution:
   2472 = $$2^3*3*103$$
   1284 = $$2^2*3*107$$
   HCF = $$2^2*3$$
   LCM = $$2^3*3^2*5*103*107$$
   HCF of the number is the highest number which divides all the numbers. So N should be a multiple of 22×3
   LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N.
   So N = [Tex]$2^2×3^2×5^1$[Tex]

7. 一个老人需要 30 分钟，一个年轻人需要 20 分钟从公寓步行到办公室。如果有一天老人早上 10 点开始，年轻人早上 10 点 05 分从公寓到办公室，他们什么时候见面？
   a) 10:00
   b) 10:15
   c) 10.30
   d) 10:45

   Answer: b) 10:15

   Solution:
   Let the distance of the apartment from the office be 12 km
   So the speed of the old man = 12 / (1/2) hr = 24 km/hr
   The young man speed = 12 / (1/3) hr = 36 km/hr
   Since the old man started 5 minutes earlier, he covers 24 × (5/60) = 2 km in 5 minutes.
   Now the time taken to the young man to meets him = 2/(36-24) * 60 = 10 minutes
   So the time of meet = 10:05 + 10 = 10 hr 15 min or 10:15

8. 在 112 到 375 的范围内，有多少个 2？
   一）312
   乙) 156
   c) 159
   d) 160

   Answer: b) 156

   Solution:
   The total number of 2’s in the units place = (122, 132, 142 … 192), (201, 212, 222, … 292), (302, 312, … 372) = 8 + 10 + 8 = 26 2’s
   The total number of 2’s in tenth’s place = (120, 121, 122, …, 129) + (220, 221, …, 229) + (320, 321, …, 329) = 30
   The total number of 2’s in hundred’s place = (200, 201, … 299) = 100.
   So the total number of 2’s between 112 and 375 = 26 + 30 + 100 = 156

9. Ram 步行 36 公里，部分速度为 4 公里/小时，部分速度为 3 公里/小时。如果他在以 4 公里的速度行走时以 3 公里/小时的速度行走，而在以 3 倍速行走时以 4 公里/小时的速度行走，那么他只会行走 34 公里。 Ram 步行的时间（以小时为单位）是
   一）10
   b) 5
   c) 12
   d) 8

   Answer: a) 10

   Solution:
   Let Ram walk ‘x’ hrs at 4 km/hr, and ‘y’ hrs at 3 km/hr.
   Given,
   4x + 3y = 36
   3x + 4y = 34
   Solving these two equations we get x + y = 10

10. PERFECT这个词的字母排列中的第55个词是什么？
    a) CEPFRET
    b) CEPFERT
    c) CEPERFT
    d) CEPRFET

    Answer: b) CEPFERT

    Solution:
    Let’s arrange the word PERFECT in dictionary order = CEEFPRT
    Here,
    CEE(4!)=24
    CEF(4!)=24
    CEPF(3!)=6
    So the 55th word is CEPFERT.