TCS 安置文件 |多选题 5

这是一份用于能力准备的 TCS 模型安置论文。这份安置文件将涵盖 TCS 招聘活动中提出的能力问题，并严格遵循 TCS 面试中提出的问题模式。建议解决以下每个问题，以增加通过 TCS 面试的机会。

下列哪个数字必须加到 5678 上才能得到 35 除以 460 的提示？
一）980
b) 618
c) 955
d) 797
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Answer: d) 797
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Solution:
Let the number added to 5678 be x to give a remainder 35 and quotient k when divided by 460.
So, 5678 + x = 460k + 35
or, 5643 + x = 460k
So 5643 + x must be divisible by 460
Ananysing from the options, we get on adding 797 to 5643, the number 6440 is divisible by 460.

编程需要懂一点英语
拉哈曼去了一家文具店，花了 100 卢比买了 18 支铅笔。他为每支灰色铅笔支付的费用比每支黑色铅笔多 1 卢比。一支灰色铅笔的价格是多少，他买了多少支灰色铅笔？
a) 5, 10 卢比
b) 6, 10 卢比
c) 5、8 卢比
d) 6、8 卢比
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Answer: b) Rs. 6, 10
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Solution:
The best way is to analyse from the mentions.
Let’s take option b in which 10 pencils are bought at Rs.6 each. So total cost of grey pencils = 6 * 10 = Rs.60. So Rahaman is left with 40 rupees. He buys 8 black pencils at Rs 5 each which is 1 rupee less than what he had spent in buying the grey ones. Thus satisfying the conditions.

编程需要懂一点英语
四个人每人掷一次四骰子。求至少两个人掷出相同数字的概率？
一种。 13/18
湾5/18
C。以上都不是
d. 1295/1296
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Answer: a) 13/18 ways
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Solution:
Total possible outcomes = = 1296
Number of ways in which no two people get same number = 6*5*4*3 = 360 ways
The probability of no two people getting the same number = 360 / 1296 ways = 5/18 ways
So the probability of at least two people getting the same number = 1 – 5/18 = 13/18 ways

编程需要懂一点英语
Ram 说 Shyam “如果你给我一半的钱，我将得到 75 卢比。” Shyam 说：“如果你给我三分之一的钱，我将有 75 卢比，Shyam 有多少钱4
c) 48
d) 60
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Answer: d) 60
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Solution: Let Ram and Shyam be denoted by ‘R’ and ‘S’ respectively
According to the question,
Eqn 1. R + S/2 = 75
Eqn 2. R/3 + S = 75
Therefore, solving both the equations we get, R = 45 and S = 60.

编程需要懂一点英语
拉姆去市场买苹果。如果他能讨价还价，将每个苹果的价格降低 2 卢比，他可以用他手头的钱买 30 个苹果而不是 20 个苹果。他有多少钱？
一种。 100 卢比
湾50 卢比
C。 120 卢比
d. 150 卢比
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Answer: c) 120
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Solution: Let the price per orange be Rs. x.
So total money Ram has in buying at original price = 20x.
On reducing the price by 2 rupees each the total money must be (x-2)*30
According to the question,
20x = (x-2)*30
On solving this we get x = 6 or the total money = Rs. 120

编程需要懂一点英语
使用数字 1、2、3 和 5 作为数字可以组成多少个小于 500 的正整数，每个数字只使用一次。
一）68
b) 34
c) 66
d) 52
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Answer: b) 34
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Solution:
Single digit numbers can be formed in 4 ways.
2 digit number can be formed in 4 * 3 = 12 ways
3 digit number less than 500 can be formed in 3 * 3 * 2 = 18 ways.
Total number of ways = 18 + 12 + 4 = 34 ways

编程需要懂一点英语
一个男孩走进一家商店，花了 y 卢比买了 x 本书。临走时，簿记员说：“再买10本书，2卢比就可以把书全部买完，一打还能省80美分”。那么 x 和 y 是什么？
a) (5, 1)
b) (10, 1)
c) (15, 1)
d) 无法确定。
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Answer: a) (5, 1)
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Solution:
x number of books cost him y rupees.
So, 1 book will cost him y/x rupees.
12 books will cost him rupees 12 y/x.
The shopkeeper says,
x + 10 books cost him 12 rupees
1 book will cost him 12/(x+10) rupees
12 books will cost him 24/(x+10) rupees
We know that 80 cents = 4/5 of a dollar,
So, 12y/x – 24/(10+x) = 4/5
Analysing the given choices, we get (5, 1) satisfies the equation.

编程需要懂一点英语
等边三角形的周长等于正六边形。找出它们的面积比？
一种。 3:2
湾1:6
C。 2:3
d. 6:1
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Answer: c) 2:3
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Solution:Let the side of the equilateral triangle be a unit and that of the regular hexagon be b unit.
So perimeter of the triangle = 3a and perimeter of the hexagon is 6b unit.
or, 3a = 6b
or a/b = 2/1
The area of the equilateral tr
iangle = $\sqrt(3)a^2/4$
The area of the regular hexagon = $3 * \sqrt(3)a^2/2$
or, $\sqrt(3)a^2/4$ : $3 * \sqr t(3)a^2/2$
Solving this and subsituting a/b we get the answer as 2 : 3

编程需要懂一点英语
在给定的系列中：70、54、45、41……。下一个数字是什么？
一）40
b) 36
c) 35
d) 38
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Answer: a) 40
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Solution:The series goes like:
70 – 54 = 16 (4^2)
54 – 45 = 9 (3^2)
45 – 41 = 4 (2^2)
41 – 40 = 1 (1^1)

编程需要懂一点英语
每隔七年出版一系列故事书。第七本书出版时，出版年总和为13524。第一本书是哪一年出版的？
一）1910
b) 1911
c) 2002
d) 1932
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Answer: b) 1911
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Solution:We get the series of publications as n, n+7, n+14, n+21, n+28, n+35, n+42.
Sum of publications = 13524 = 7/2[2n + (7-1)*7] (Using the sum of AP formula)
We get, n = 1911 (answer)

编程需要懂一点英语