TCS 安置文件 |多选题 3

这是一份用于能力准备的 TCS 模型安置论文。这份安置文件将涵盖 TCS 招聘活动中提出的能力问题，并严格遵循 TCS 面试中提出的问题模式。建议解决以下每一个问题，以增加通过 TCS 面试的机会。

如果 f(x) = ax^4 – bx^2 + x + 5 并且给定 f(-3) = 2，那么 f(3) = ? （a^b = a 的 b 次幂）
一）3
b) 8
c) 1
d) -2
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Answer: b) 8
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解决方案：

We can directly solve:
=> f(-3) = a(-3)^4 – b(-3)^2 + (-3) + 5 = 2
=> 81a – 9b + 2 = 2
=> 81a – 9b = 0
Now solving f(3),
=> f(3) = 81a – 9b + 8
=> f(3) = 0 + 8 = 8(Answer)

编程需要懂一点英语
有一家巧克力工厂，向班级分发巧克力。它为 50 名学生的班级提供 30 天的巧克力，请记住，所有学生都获得相同数量的巧克力。在最初的 10 天里，只有 20 名学生在场。有多少学生被容纳到小组中，以便所有的巧克力都被消耗掉？
一）70
b) 55
c) 60
d) 45
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Answer: d) 45
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解决方案：

Let each student get 1 chocolate each, so the total number of chocolates = 50 * 30 = 1500 chocolates.
For first 10 days 20 students were present, so total chocolates consumed = 20 * 10 = 200 chocolates.
Chocolates left = 1300. These are to be distributed for the next 20 days. Therefore in each day 1300 / 20 chocolates were to be consumed which = 65 chocolates per day.
So the required answer = 65 – 20 = 45 chocolates.

编程需要懂一点英语
给定 log(0.318) = 0.3364 和 log(0.317) = 0.3332，找到 log(0.319)？
a) 0.3396
b) 0.3394
c) 0.3393
d) 0..390
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Answer: a) 0.3396
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解决方案：

=> log(0.319) = log(0.318) + (log(0.318) – log(0.317))
= 0.3364 + (0.3364 – 0.3332)
= 0.3364 + 0.0032
= 0.3396 (Answer)

编程需要懂一点英语
有一组20名学生，其中18名是男孩，2名是女孩。他们要坐成圆形，这样两个女孩总是被一个男孩隔开。学生有多少种安排？
一）12
b) 18!x2
c) 17×2！
d) 17！
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Answer: b) 18!x2
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解决方案：

There are in all 20 places out of which if one girl sits in one position then the other girl may sit either to her left or right skipping one place, which is to be filled by a boy. So total number of ways the boys can sit = 18! ways and girls may alternate there sits so the total answer would be = 18! * 2 ways.

编程需要懂一点英语
拉姆出现在考试中。在论文 A 中他得了 18 分（满分 70 分）。在论文 B 中他得了 14 分（满分 30 分）。那么他在哪篇论文中表现更好呢？
a) 论文 A
b) 纸 B
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Answer: b) Paper B
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解决方案：

We just need to calculate the percentage he scored in each paper.
In paper A: (18/70) * 100 = 25.7%
In paper B: (14/30) * 100 = 46.6% (Answer)

编程需要懂一点英语
一架航班于凌晨 2 点从 18N 10E 的一个地方起飞，并在 10 小时后于 36N 70W 降落。目的地当地时间是几点？
a) 早上 6:00
b) 早上 6:40
c) 上午 7:40
d) 上午 7:00
e) 上午 8:00
```
Answer: b) 6:40 a.m
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解决方案：

Let’ calculate the difference in the number of latitudes = 70 + 10 = 80 degrees towards east.
We know 1 degree = 4 min, so 80 degrees = 80 * 4 = 320 mins
320 mins = 5 hr 20 minutes
Now the plane landed 10 hours later so time of landing = 12 hrs according to the starting place
So time at destination = 12 hrs – 5 hrs 20 min = 6 hr 40 mins(Answer)

编程需要懂一点英语
沿着铁轨以 9 公里/小时的速度进行的运动跑。轨道长 240m，在同一方向以 45km/hr 运行的 120m 火车前面。火车完全越过运动员需要多长时间？
a) 3.6 秒
b) 18 秒
c) 72 秒
d) 36 秒
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Answer: d) 36 sec 
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解决方案：

Let’s try to find the relative speed = 45 – 9 = 36km/hr
= 36 * 5/18 = 10m/s
Now the total distance needed to be covered by the train to completely cross the athlete = 240 + 120 = 360m
So time = dist/speed = 360/10 = 36 seconds

编程需要懂一点英语
A 需要 3 天才能完成一项工作，而 B 需要 2 天。他们俩都完成了一项工作并赚取了卢比。 150. A 的钱份额是多少？
一）卢比。 70
b) 卢比。 30
c) 卢比。 60
d) 卢比。 75
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Answer: c) 60
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解决方案：

A completes 1/3rd of work in one-day and B completes 1/2 of work in one day. So the ratio of there work is:
A:B = 2:3
So A’s share = (2/5)*150 = 60 rupees(Answer)

编程需要懂一点英语
Ram 和 Shyam 的工资比例为 2:3。如果两者的工资各增加 4000 卢比，则新比率变为 40:57。 Shyam 现在的工资是多少？
一）卢比。 17, 000
b) 卢比。 20, 000
c) 卢比。 25, 500
d) 这些都不是
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Answer: d) None of these
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解决方案：

Let Rams and Shyams salary be ‘x’. The ratio of there salary according to the question is 2x:3y
According to the question,
(2x+4000):(3x+4000) = 40:57
On solving we get 3x = 34000
Therefore, the present salary of Shyam is Rs. 34000

编程需要懂一点英语
在 10 年后，一笔钱的 SI 将是该金额的 2/5，以每年的多少百分比计算？
a) 6%
b) 5 2/3 %
c) 4%
d) 6 2/3 %
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Answer: c) 4%
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解决方案：

Let the sum of money be Rs ‘x’. So SI = 2x/5
So, rate = (SI*100)/(P*Time)
=> (2x*100)/(5*x*10)
=> 4 % (Answer)

编程需要懂一点英语